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3 years ago

What is 2r+7+r=? I'm not sure

Mathematics

2 answers:

Alexus [3.1K]3 years ago

7 0

2r + 7 + r = ?

Combine like terms.

(2r + r) + 7

Simplify.

3r + 7

~Hope I helped!~

marissa [1.9K]3 years ago

5 0

3r+7 I think...........

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The perimeter of a rectangular banner is 72 inches. The width of the banner is 1/3 its length. What is the area of the banner?

muminat

Answer:

144

Step-by-step explanation:

If you multiply 4 by 12, then add 100, you get 144 which is the area.

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2 years ago

Applying properties to write equivalent expressions for 2x+5y+5(2x+5y)

levacccp [35]

Solving expression $2x+5y+5(2x+5y)$ we get $12x+30y$

Step-by-step explanation:

We need to solve the expression:

$2x+5y+5(2x+5y)$

Solving:

Multiplying 5 with terms inside the bracket:

$2x+5y+5(2x+5y)\\=2x+5y+10x+25y\\Combining\,\,like\,\,terms:\\=2x+10x+5y+25y\\=12x+30y$

So, Solving expression $2x+5y+5(2x+5y)$ we get $12x+30y$

Keywords: Solving Expressions

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7 0

2 years ago

1 point

Margarita [4]

Answer:

35% or 0.35

Step-by-step explanation

If 20 grams is 100%, that means each gram is 5% of the whole. So 7 time 5 is 35.

4 0

3 years ago

1/2(x + 5)2 + 2 = 42.5

Monica [59]

Answer:

x=35.5

Step-by-step explanation:

reduce numbers

remove parentheses

add the numbers

move constant to the right

subtract numbers

7 0

2 years ago

Read 2 more answers

Find the area of the shaded region

o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)$

$A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}$

5 0

1 year ago