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BartSMP [9]
4 years ago
9

A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)

Mathematics
2 answers:
borishaifa [10]4 years ago
4 0
To solve this problem you must apply the proccedure shown below:

 1. The vertex i at <span>(0, 36) and a focus at (0, 39), then you have:

 a=36
 a^2=1296

 2. The directrix is:

 y=a^2=c
 c=39
 y=1296/39
 </span>y=432/13<span> 

 Therefore, the answer is the option D, which is: </span><span>D. y=± 432/13</span>
solniwko [45]4 years ago
4 0

Answer:

D. y=± 432/13

Step-by-step explanation:

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