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3 years ago

A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)

2 answers:

4 0

To solve this problem you must apply the proccedure shown below:

1. The vertex i at (0, 36) and a focus at (0, 39), then you have:

a=36
a^2=1296

2. The directrix is:

y=a^2=c
c=39
y=1296/39
y=432/13

Therefore, the answer is the option D, which is: D. y=± 432/13

solniwko [45]3 years ago

4 0

Answer:

D. y=± 432/13

Step-by-step explanation:

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