Question

A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)

Answer 1

To solve this problem you must apply the proccedure shown below:

 1. The vertex i at (0, 36) and a focus at (0, 39), then you have:

 a=36
 a^2=1296

 2. The directrix is:

 y=a^2=c
 c=39
 y=1296/39
 y=432/13 

 Therefore, the answer is the option D, which is: D. y=± 432/13

Answer 2

Answer:

D. y=± 432/13

Step-by-step explanation: