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3 years ago

A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)

2 answers:

4 0

To solve this problem you must apply the proccedure shown below:

1. The vertex i at (0, 36) and a focus at (0, 39), then you have:

a=36
a^2=1296

2. The directrix is:

y=a^2=c
c=39
y=1296/39
y=432/13

Therefore, the answer is the option D, which is: D. y=± 432/13

solniwko [45]3 years ago

4 0

Answer:

D. y=± 432/13

Step-by-step explanation:

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The owners of Shaving Ice are concerned that many of their customers are starting to purchase their icy treats from Cold as Ice

harkovskaia [24]

Answer:

The correct option is;

$4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$

Step-by-step explanation:

Here we have the formula for the confidence interval of the difference of two means where the population standard deviation is unknown based on the sample mean and sample standard deviation is given as follows;

$\left (\bar{x}_{1}- \bar{x}_{2} \right )\pm t_{\alpha /2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}$

Where:

$\bar{x}_{1}$ = Mean of the first sample = 22 grams

$\bar{x}_{2}$ = Mean of the second sample = 18 grams

s₁ = Sample standard deviation of the first sample = 3.2 grams

s₂ = Sample standard deviation of the second sample = 2.1 grams

n₁ = Sample size of the first sample = 100

n₂ = Sample size of the second sample = 100

$t_{\alpha /2}$ = t value obtained from tables at 99% confidence level and 100 degrees of freedom = 2.626 = 2.63

Therefore, plugging in the values, we have;

$\left (22- 18 \right )\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}} = 4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$

Therefore, the correct option is $4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$ .

4 0

3 years ago

What’s 3x+6y=12 in the form y=mx+b

zhenek [66]

Hey there!

3x+6y=12

Divide both sides by 3 and your equation would now look like:
x+2y= 4
Move the x to the other side
2y= -x+4
Seprate the y by dividing both sides by 2
y= $\frac{1}{2}$ x+2

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If the equation y = 15x + 2 is changed to y = 15x - 4, how will the graph of the line change?

igomit [66]

The y-intercept is changed from 2 to -4.

That means that the point that the graph crosses the y axis has been moved down by 6.

Since the slope of the line has not changed, this just means the graph of the line will be moved down by 6.

Hope this helps!
Your fortune is "When given a difficult choice, trust your gut. If you don't have one, then close your eyes and hope for the best."

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3 years ago

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Classify each figure on the triangle

ipn [44]

All the triangles are isosceles meaning that they have to sides that are equal

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Solve for d –3d + 10 − 5d = –10 − 10d

deff fn [24]

Your answer would be -2

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