The graph highlights two other points on the trend line. Use them to find another equation for the trend line shown for this sca
tter plot.
Y=82x+998 , Y=247.7x-335 , Y=743x-1647 , Y=998+82 ?
Y=82x+998 , Y=247.7x-335 , Y=743x-1647 , Y=998+82 ?
2 answers:
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Answer:
The weight of Pedro on Mars is 266.4 N
Step-by-step explanation:
It is given that,
Mass of Pedro, m = 72 kg
Let W is the weight of Pedro on the Mars. We know that the product of mass and the acceleration due to gravity is called the weight on an object. Mass remains same everywhere. It can be calculated as :
g is the gravitational field strength on Mars, g = 3.7 N/kg
W = 266.4 N
So, the weight of Pedro on Mars is 266.4 N. Hence, this is the required solution.
*see attachment for the complete diagram and what is required.
Answer:
✅ST = 7 m
✅SU = 8 m
✅m<R = 46°
✅m<Q = 75°
✅m<S = 59°
Step-by-step explanation:
Given that ∆PQR ≅ ∆STU, therefore, their corresponding sides and angles would be congruent to each other.
Thus:
<P ≅ <S, therefore, m<P = m<S = 59°
<Q ≅ <T, therefore, m<Q = m<T = 75°
<R ≅ <U, therefore, m<R = m<U.
PQ ≅ ST, therefore, PQ = ST
QR ≅ TU, therefore, QR = TU
PR ≅ SU, therefore, PR = SU
Let's find the measure of the following with the information we already know:
✅ST = PQ = 7 m
✅SU = PR = 8 m
✅m<R = 180 - (m<P + m<Q) (sum of ∆)
m<R = 180 - (59°+ 75°) (substitution)
m<R = 180 - 134
m<R = 46°
✅m<Q = m<T = 75°
✅m<S = m<P = 59°
