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3 years ago

Will mark brainliest. please help

Mathematics

1 answer:

kobusy [5.1K]3 years ago

5 0

Answer:

the answer is 53 degrees

Step-by-step explanation:

the coordinating angle to angle 1 is 53 degrees. they are congruent so they have the same angle

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the mall is 84 meters long. the post office is 38 meters long. how much longer is the mall than the post office

Flauer [41]

Step-by-step explanation:

length of mall=84m

length of post office=38m

how much longer is the mall than the post office=84-38= 46m

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3 years ago

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Which percentage is greater??<br><br> 57.68 <br> or<br> 57.8%

alexandr1967 [171]

57.8% is greater than 57.68%

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3 years ago

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The answer to this question that I’ve been stuck on for a long time

Norma-Jean [14]

Answer:

x = -3/2

Step-by-step explanation:

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3 years ago

Assume X is normally distributed with a mean of 5 and a standard deviation of 2. Determine the value for x that solves each of t

mihalych1998 [28]

Answer:

U = 5

S = 4

1.) P(X>x) = 0.5

Prob = 1-0.5 = 0.5

We have z = 0, that is the z score with the probability of 0.5

X = u + z(s)

= 5+0*4

= 5

2.) 1-0.95 = 0.05

Z score having this probability

Z = -1.64

X = 5-1.64*4

= 5-6.56

= -1.56

3.) P(z<1.0) - p(X<x) = 0.2

0.841345-0.2 = .641345

We find the z score given this probability

Z= 0.36

X = 5+0.36*4

= 5+1.44

= 6.44

4.) P(X<x)-P(Z<-.5)

0.95 = p(X<x)-0.308538

p(X<x) = 0.308538 + 0.95

= 1.258538

There is no x value here, given that the probability is more than 1.

5. 1-0.99/2 = 0.005

We get the z score value

= -2.58

U - 5 = 5-5 = 0

-x = 0-2.58(4)

X = 10.32

5 0

3 years ago

The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s

lys-0071 [83]

Answer:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

$IQR = Q_3 -Q_1 = 250-210 =40$

For this case we need to find the lower and upper limit with the following formulas:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0

4 years ago