Answer: A.) Probability is approximately 5%
B.) probability that Die1 + Die + Die > 12 is approximately 26%
Step-by-step explanation:
Total possible outcomes of the three dies (sample space) = (6^3) = 216
For die1 + die2 + die3 to be equal six, then the number of outcomes which produces our required outcome from the sample space is = 6
Therefore, probability of die1 + die2 + die3 = 6 is given by;
P(die1 + die2 + die3 = 6) = total required outcome / total possible outcomes
P(die1 + die2 + die3 = 6) = 10/216
P( die1 + die2 + die3 = 6) = 0.04629
P( die1 + die2 + die3 = 6) = 4.63% approximately 5%
B) probability that Die1 + Die + Die > 12
P(Die1 + Die + Die > 12) = 57/216 = 0.2638
= 26.38%
Approximately 26%
a c and d
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Answer: True
Step-by-step explanation:
True
Suppose length is X -----> [1]
so the width is X - 5 -----> [2]
perimeter of rectangle = 2 ( length + width )
50 = 2 ( X + X - 5 )
50 = 2 ( 2X - 5 )
50 = 4X - 10
50 + 10 = 4X
60 = 4X
60/4 = X
15 = X
subsitute in [1] and [2]
length = 15 meters
width = 15 - 5 = 10 meters