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a_sh-v [17]
3 years ago
15

ASAP Plz what is the value of x? Plz no joking around this is from quiz 4.09: Special Right Triangles 2

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
Ooh this is a good one!
Firstly, let's find RT so that we can solve the top triangle.
We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)

For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
s \sqrt{3}  = 2 \sqrt{3}  \\ s \sqrt{3} \div  \sqrt{3}   = 2 \sqrt{3} \div  \sqrt{3}  \\ s = 2
So now, the hypotenuse (RT) = 2s = 2(2) = 4

Secondly, we are looking at the other type of special right triangle, the 45-45-90:
The side opposite the 45s are s (remember side lengths are equal whose opposite angles are equal); and the hypotenuse is always
s \sqrt{2}
we only need QR, which is s, which is also = RT
So the answer is:
QR = x = 4

x = 4 IS THE FINAL ANSWER!!!


[ i hope by my explanations you understand how better to do special right triangles in the future] :-D
ch4aika [34]3 years ago
5 0

Answer: The correct answer is 4

Step-by-step explanation:

Here is proof from the quiz

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3 years ago
Read 2 more answers
The probability of a successful optical alignment in the assembly of an optical data storage product is p = 0.7. Assume the tria
zhannawk [14.2K]

Answer:

(a) P(X = 4) = 0.0189

(b) P(X \leq 4) = 0.9919

(c) P(X \geq 4) = 0.027

Step-by-step explanation:

We are given that the probability of a successful optical alignment in the assembly of an optical data storage product is p = 0.7 .

Since we have to find the probabilities for 1st successful alignments, so the probability distribution that we will use here is Geometric distribution.

<u>Geometric distribution</u> is used when we are interested in knowing the chances of our first success.

The probability distribution of geometric distribution is given by;

P(X =x) = p(1-p)^{x-k} ; x = 1,2,3,....

where, x = number of trials

            k = first success = 1

            p = probability of getting success = 0.70

So, X ~ Geo(p = 0.7)

(a) Probability that the 1st successful alignment requires exactly 4 trials is given by = P(X = 4)

Here, x = 4, p = 0.7 and k = 1

So, P(X = 4) = 0.7(1-0.7)^{4-1} = 0.7 \times 0.3^{3} = 0.0189

(b) Probability that the 1st successful alignment requires at most 4 trials is given = P(X \leq 4)

 P(X \leq 4) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)  

               = 0.7(1-0.7)^{1-1} + 0.7(1-0.7)^{2-1}+0.7(1-0.7)^{3-1}+0.7(1-0.7)^{4-1}

               = 0.7 \times 0.3^{0}+0.7 \times 0.3^{1}+0.7 \times 0.3^{2}+0.7 \times 0.3^{3}

               = 0.7 + 0.21 + 0.063 + 0.0189 = 0.9919

(c) Probability that the 1st successful alignment requires at least 4 trials is given by = P(X \geq 4)

    P(X \geq 4) = 1 - P(X < 4) = 1 - P(X \leq 3)

    P(X \geq 4) = 1 - P(X = 1) - P(X = 2) - P(X = 3)

                  =  1-0.7(1-0.7)^{1-1} + 0.7(1-0.7)^{2-1}+0.7(1-0.7)^{3-1}

                  = 1-0.7 \times 0.3^{0}+0.7 \times 0.3^{1}+0.7 \times 0.3^{2}

                  = 1 - 0.7 - 0.21 - 0.063 = 0.027

8 0
3 years ago
Please help and thank you
qwelly [4]

when you multiply exponents, they add together and the base will remain the same:

-5+-2

=-7

therefore the answer is 8^-7

to get rid of the negative, flip the fraction so it becomes

1/8^7

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Lim ln(tan x) as tends to pi/2 from the left
ioda
Let x=\arctan y. Then \tan x=y, and so as x\to\dfrac\pi2^-, you have y\to+\infty. The limit is then equivalent to

\displaystyle\lim_{x\to\frac\pi2^-}\ln(\tan x)=\lim_{y\to\infty}\ln y=\infty
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After your instructor added 4 points to each student's test score, your score is 92.
Alexandra [31]
88

92-4=88

hope this helps
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2 years ago
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