3 years ago

Rewrite each expression as a single power (-5^5)^2

Mathematics

1 answer:

zvonat [6]3 years ago

6 0

Answer: 5^10

Step-by-step explanation:

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Sedaia [141]

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Step-by-step explanation:

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2 years ago

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For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

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3 years ago

$1876 per month for 12 months<br> A) $22,512<br> B) $225.12<br> c) $1888<br> D) None of these

insens350 [35]

Answer:

The answer is A

Step-by-step explanation:

We need to multiply 1876 by 12. 1876 * 12 = 22, 512. That's our answer

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3 years ago

4xsquared 12x 10 is less than or equal to 0 (or what multiplies to get 40 and adds to get 12)

g100num [7]

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3 years ago