The equation of a line is written in form y = Mx+ b
M is the slope, also known as the gradient.
You are given the gradient and one point , which is an x and y value. Using that solve for b:
1. Gradient = 2, x = 4, y= 3
3 = 2(4) + b
3 = 8 + b
Subtract 8 from both sides:
B = -5
The equation becomes y = 2x-5
2. Gradient = -3, x= -1, y = 7
7 = -3(-1) + b
7 = 3 + b
Subtract 3 from both sides:
B = 4
Equation becomes: y = -3 +4
Hi sorry for the late response, I know the assignment was due at 5pm today but anyway here is the answer.
System:
<em>d= 5(0.75-t)</em>
<em>d= 20t</em>
<em>20t = 3.75 -5t</em>
Define Variables:
<em>d = how far Carol Skied</em>
<em>t = time it took Carol to go up/down</em>
Solve:
20t = 3.75 -5t
20t + 5t = 3.75 -5t + 5t
25t = 3.75
25t/25 = 3.75/25
t = 0.15
<u><em>Now we plug in the time into the Distances:</em></u>
20t = 3.75 - 5t
20(0.15) = 3.75 - 5(0.15)
3 = 3.75 - 0.75
3 = 3
Solution as Sentence:
<u><em>Carol Skied 3 miles</em></u>
<u><em /></u>
3, 4, 5, 6 and 7
Q 1= (3+4)/2=3.5
Q 2= (4+5)/2=4.5
Q 3=(5+6)/2=5.5
Interquartile range =Q3-Q1
=5.5-3.5
=2
Answer:
x = -4, 14
Step-by-step explanation:
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