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2 years ago

14

How many solutions does the system have? \begin{cases} & y = 2x-1 \\\\ & y = 2x+6 \end{cases} ⎩ ⎪ ⎨ ⎪ ⎧ y=2x−1 y=2x+

6

1 answer:

coldgirl [10]2 years ago

8 0

Answer:

A) y=2x−1

B) y=2x+6

The equations reduce to:

-1 = 6

Which is NOT true so those equations have NO solution.

Step-by-step explanation:

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Step-by-step explanation:

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1 year ago

What is the derivative of the following function? f(x) = 4x^6/cos^5(x)

KIM [24]

Answer:

$f'(x) = \frac{24x^{5} \cos x + 20x^{6}\sin x}{\cos^{6}x }$

Step-by-step explanation:

We have to find the derivative of the following function:

$f(x) = \frac{4x^{6} }{\cos^{5} x }$

Now, differentiating both sides with respect to x we get,

$f'(x) = \frac{\cos^{5}x (24x^{5}) - 4x^{6}(5\cos^{4}x )(- \sin x)}{(\cos^{5}x )^{2}}$

⇒ $f'(x) = \frac{ 24x^{5} \cos x + 20 x^{6}\sin x}{\cos^{6}x }$ (Answer)

{Since, we know that, $\frac{d(mx^{n} )}{dx} = m \times n x^{(n - 1)}$ and $\frac{d(\cos^{n} x)}{dx} = n \cos^{(n - 1)} x(- \sin x)$ }

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3 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

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Answer:

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Step-by-step explanation:

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