Question

Type the correct answer in the box use numerals instead of words

Answer 1

Answer:

Subtracting $3x^2+4x-5$ from $7x^2+x+9$ results in a polynomial. After subtracting $4x^2-3x$ from this polynomial the difference is 14

Step-by-step explanation:

The question given is:

Subtracting $3x^2+4x-5$ from $7x^2+x+9$ results in a polynomial. After subtracting $4x^2-3x$ from this polynomial the difference is?

First we will Subtracting $3x^2+4x-5$ from $7x^2+x+9$

$7x^2+x+9-(3x^2+4x-5)\\=7x^2+x+9-3x^2-4x+5\\Combining\:like\:terms\\=7x^2-3x^2+x-4x+9+5\\=4x^2-3x+14$

So, the polynomial we get is: $4x^2-3x+14$

Now, subtracting $4x^2-3x\: from\: 4x^2-3x+14$

$4x^2-3x+14-(4x^2-3x) \\=4x^2-3x+14-4x^2+3x\\Combining\:like\:terms\\=4x^2-4x^2-3x+3x+14\\=14$

The difference is 14

So, Subtracting $3x^2+4x-5$ from $7x^2+x+9$ results in a polynomial. After subtracting $4x^2-3x$ from this polynomial the difference is 14