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OleMash [197]
3 years ago
5

Amanda sells beaded necklaces. Each large necklace sells for $5.70 and each small necklace sells for $4.60. How much will she ea

rn from selling 1 large necklace and 6 small necklaces?
PLS SOMEONE HELP ME!​
Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

Step-by-step explanation:

large necklace; $5.70

$4.60 x 6= $27.60

$33.30 total

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Answer:

V = 1385.44

Step-by-step explanation:

The equation for volume is V = π r 2 h! Where V = volume, r = radius <em>(half the diameter)</em>, and h = height. Now lets substitute what we know into this equation!

<em>Since we are giving the diameter (14) we must divide by 2 to find the radius.</em>

                         14 ÷ 2 = 7

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V = ?

Time to plug these values in!

V = π 7^{2} (9)

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It takes Gaby only a few hours to read a long book. Which is the dependent variable in this situation?
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<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
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3 years ago
Which function has an average rate of change of -4 over the interval [-2,2]?
kolbaska11 [484]

Only p(x) has an average rate of change of -4 over [-2, 2].

Find the average rate of change of each given function over the interval [-2, 2]]:

The average rate of change of m(x) over [-2, 2]:

<h3>What is the average rate?</h3>

The average rate of change = \frac{m(b)-m(a)}{b-a}

Where, a = -2, m(a) = -12

b = 2, m(b) = 4

Plug the values into the equation

The average rate of change

=\frac{4-(-12)}{2-(-2)} =\frac{16}{4}

The average rate of change = 4

The average rate of change of n(x) over [-2, 2]:

The average rate of change = \frac{n(b)-n(a)}{b-a}

Where, a = -2, n(a) = -6

b = 2, n(b) = 6

Plug the values into the equation

The average rate of change

=\frac{6-(-6)}{2-(-2)} \\=\frac{12}{4}

The average rate of change = 3

The average rate of change of q(x) over [-2, 2]:

The average rate of change = \frac{q(b)-q(a)}{b-a}

Where, a = -2, q(a) = -4

b = 2, q(b) = -12

Plug the values into the

The average rate of change = \frac{-4-12}{2-(-2)}

= \frac{-16}{4}

The average rate of change = -2

The average rate of change of p(x) over [-2, 2]:

The average rate of change = \frac{p(b)-p(a)}{b-a}

Where, a = -2, p(a) = 12

b = 2, p(b) = -4

Plug the values into the equation

The average rate of change = \frac{-4-12}{2-(-2)}

=\frac{-16}{4}

The average rate of change = -4

The answer is D.

Only p(x) has an average rate of change of -4 over [-2, 2].

To learn more about the average rate of visit:

brainly.com/question/8728504

#SPJ1

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