A triangle has vertices at L:(4, 4), M:(7, 4), and N:(5, 2).
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Answer:
0.7325 to 5.6675 ug/dl
Step-by-step explanation:
The middle 90% will be 45% above the mean and 45% below the mean. This means
0.5-0.45 = 0.05 and
0.5+0.45 = 0.95
We use a z table. Look in the cells; find the values as close to 0.05 and 0.95 as we can get.
For 0.05, we have 0.0505 and 0.0495; since these are equidistant from 0.05, we use the value between them. 0.0505 is z=-1.64 and 0.0495 is z=1.65; this gives us z=-1.645.
For 0.95, we have 0.9495 and 0.9505; since these are equidistant from 0.95, we use the value between them. 0.9495 is z = 1.64 and 0.9505 is z=1.65; this gives us z = 1.645.
Now we use our z score formula,
Our two z scores are 1.645 and -1.645; our mean, μ, is 3.2; and our standard deviation, σ, is 1.5:
Multiply both sides by 1.5:
Add 3.2 to each side:
2.4675+3.2 = X-3.2+3.2
5.6675 = X
Multiply both sides by 1.5:
Add 3.2 to each side:
-2.4675+3.2 = X-3.2+3.2
0.7325 = X
Our range is from 0.7325 to 5.6675.
There are a couple of different ways you could do this, but I'll show the simpler way. We will use the formula
along with the fact that the vertex has h and k coordinates of 1 and 4 respectively, and that a point on the graph is (3, 5). We could have used any point on the graph where there is a definite integer coordinate pair. We will fill in accordingly and solve for a.
and
5 = 4a + 4. If we subtract 4 from both sides we get that . Now we will fill in the formula and expand as needed:
and
. If we distribute the 1/4 in and then add the constants the final equation for that graph will be