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Ray Of Light [21]
2 years ago
15

A triangle has vertices at L:(4, 4), M:(7, 4), and N:(5, 2).

Mathematics
1 answer:
e-lub [12.9K]2 years ago
5 0
Good luck to you! Ask if you have questions!

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If you plan to receive $300 of interest over 15 months on an initial investment of $1200, what is the nominal annual rate of int
Romashka [77]

Answer:

£5566 the answer is no longer be available for remote

5 0
2 years ago
Suppose ACT Reading scores are normally distributed with a mean of 21.4 21.4 and a standard deviation of 5.9 5.9 . A university
Nutka1998 [239]

Answer:

29.2

Step-by-step explanation:

Mean = 21.4

Standard deviation = 5.9%

The minimum score required for the scholarship which is the scores of the top 9% is calculated using the Z - Score Formula.

The Z- score formula is given as:

z = x - μ /σ

Z score ( z) is determined by checking the z score percentile of the normal distribution

In the question we are told that it is the students who scores are in the top 9%

The top 9% is determined by finding the z score of the 91st percentile on the normal distribution

z score of the 91st percentile = 1.341

Using the formula

z = x - μ /σ

Where

z = z score of the 91st percentile = 1.341

μ = mean = 21.4

σ = Standard deviation = 5.9

1.341= x - 21.4 / 5.9

Cross multiply

1.341 × 5.9 = x - 21.4

7.7526 = x -21.4

x = 7.7526 + 21.4

x = 29.1526

The 91st percentile is at the score of 29.1526.

We were asked in the question to round up to the nearest tenth.

Approximately, = 29.2

Step-by-step explanation:

7 0
3 years ago
in a class, 60% of the students are girls. there are 19 girls in the class. how many students are there? how many boys are there
Slav-nsk [51]
60/40 =19/? 19 ×40÷60=13 there is 13 boys
4 0
3 years ago
There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45
4vir4ik [10]
I'm only going to complete Part B. The other two are a bit easier and I believe you can do it! :D
Neighborhood A
----------------------------
Year 1: 30 increased by 20% = 6 more homes.
Year 2: 36 increased by 20% = 7.2 more homes ... 7 more homes. You cannot round in these types of problems.
Year 3: 43 increased by 20% = 8.6 ... 8 more homes.
Year 4: 51 increased by 20% = 10.2 ... 10 more homes.
Year 5: 61 increased by 20% = 12.2 ... 12 more homes.
At the end of 5 years Neighborhood A will have 73 homes in total.

Neighborhood B
---------------------------
Year 1: 45 +3 = 48
Year 2: 48 +3 = 51
Year 3: 51 +3 = 54
Year 4: 54 +3 = 57
Year 5: 57 +3= 60 homes
After 5 years Neighborhood B will have 60 homes.
Hope this helped! I will do Part A or Part C later if I have time and you still need assistance. 
3 0
2 years ago
En un censo realizado en escuelas de enseñanza media superior de un municipio, participaron 8 escuelas que indicaron la cantidad
Harrizon [31]

Answer:

In a census carried out in upper secondary schools in a municipality, 8 schools participated, indicating the number of students who graduated in a given year. The data is shown in the following graph and according to this, what was the average number of graduated students?

Step-by-step explanation:

This is what it says in english

7 0
3 years ago
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