I’m pretty sure it’s 2.99
Area of a triangle is A = (1/2) (b) (h). Here we are given A and b and need to find h.
A = 24 ft^2 = (1/2) (4 ft) (height)
24 = 2(height) => height is 12 ft (answer)
Answer:
Part A: Two pieces of information that are provided by the graph is the median which is 55 and the range which is 20-95. Two piece of information that is not provided by the graph is the mean and mode.
Part B: The interquartile range of the data is 25. It represent the range between the amount of time in minutes that the students of a class surfed the internet.
I am not sure if this is all correct, but i tired. I hope this helps :)
Answer:
m∠K = 37° and n = 31
Step-by-step explanation:
A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:
- a² = b² +c² -2bc·cos(A)
- k² = 31² +53² -2·31·53·cos(37°)
<h3>Comparison</h3>
Comparing the two equations, we note these correspondences:
Comparing these values to the given information, we see that ...
- KN = c = 53 . . . . . . . . . . matching values 53
- NM = a = k . . . . . . . . . . . matching values k
- KM = b = n = 31 . . . . . . . matching values 31
- ∠K = ∠A = 37° . . . . . . . matching side/angle names
Abby apparently knew that ∠K = 37° and n = 31.
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<em>Additional comment</em>
Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.
Vertex and angle K are opposite side k, also called side NM in this triangle.
Step-by-step explanation:
As we can see, the line on the bottom is a perfectly straight 180º line, so the two angles, a and 50º are supplementary angles. Remember: Supplementary angles = 180º, and complementary angles = 90º.
Since this is a 180º line, all we have to do is to subtract 50 from 180 to get our angle a.
180-50 = 130º
Our answer: a = 130º
