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Sedbober [7]
3 years ago
7

The circle below is centered at the point (8,4) and has a radius of length 4.

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

\textbf{The equation of the circle is: $ {(x-8)}^2 + {(y-4)}^2 = 16 $.}\\

Step-by-step explanation:

\textup{The equation of a circle is given by:}\\$$c = \sqrt{{(x-h)}^2 + {(y-k)}^2} = r^2$$\\\textit{where $(h,k)$ represents the centre of the circle and $r$ the radius.}\\\textup{Given the centre of the circle is $(8,4)$ and radius is $4$.}$ \therefore $ We have $$c = \sqrt{{(x-8)}^2 + {(y-4)}^2} = 4^2$$$\implies {(x-8)}^2 + {(y-4)}^2 = 16$

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