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3 years ago

The circle below is centered at the point (8,4) and has a radius of length 4.

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

Answer:

$\textbf{The equation of the circle is: $ {(x-8)}^2 + {(y-4)}^2 = 16 $.}\\$

Step-by-step explanation:

$\textup{The equation of a circle is given by:}\\$$c = \sqrt{{(x-h)}^2 + {(y-k)}^2} = r^2$$\\\textit{where $(h,k)$ represents the centre of the circle and $r$ the radius.}\\\textup{Given the centre of the circle is $(8,4)$ and radius is $4$.}$ \therefore $ We have $$c = \sqrt{{(x-8)}^2 + {(y-4)}^2} = 4^2$$$\implies {(x-8)}^2 + {(y-4)}^2 = 16$$

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Enter the decimal 1.45 as an improper fraction in simplest form.

scZoUnD [109]

Answer:

29/20

Step-by-step explanation:

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3 years ago

Read 2 more answers

Two sizes of cans of beans are similar. The thickness of the walls and bases are the same in both cans. The ratio of their surfa

agasfer [191]

Answer:

It costs $0.216 to make smaller can and $0.324 to make larger can

Step-by-step explanation:

Given:

The ratio of the surface areas = 4:9

Area of smaller cans = 36 sq in

Cost = $0.006 per square inch

To Find:

how much does it cost to make each can = ?

Solution:

Lets the area of the larger can be x

the ratio is 4 : 9

then 4x = 9.(36)

4x = 216

$x = \frac{216}{4}$

x = 54

The area of the larger can is 54 sq in

Now the cost of making the smaller can = $36 \times 0.006$ = $0.216

The cost of making the Larger can = $54 \times 0.006$ =$0.324

4 0

3 years ago

Find w and y, will give brainliest for the correct answer

Alex Ar [27]

Answer: w=12, y=6√3

Step-by-step explanation:

Looking at the figure, we can split the triangle into 2 separate triangles. One on the left and one on the left. The triangle on the right is a 30-60-90 triangle. For this triangle, the hypotenuse is 2x in length. This is directly opposite of the right angle. The leg opposite to 30° is x in length. The leg opposite 60° is x√3 in length. Once you know the length of one side, you can plug in x to find the length of the other legs.

In this case, w and y are located on the same 30-60-90 triangle. Normally we would focus on that triangle to find our values, but in this instance, we don't have any values. We have to use the left triangle to find the leg that both triangles share.

The left triangle is a 45-45-90 triangle. For this triangle, the legs opposite of 45° is x in length. The hypotenuse is x√2. Since we know the hypotenuse, we can use it to find x.

x√2=8

x=8/√2

x=5.7 or 6 [Let's use 6 so that it is easier to work with a whole number]

Now that we know x, we can find w and y. Going back to the right triangle, we know the hypotenuse is 2x. We plug in 6 to find the length.

w=2x

w=2(6)

w=12

We know the leg opposite of 60° is x√3. We can plug in x.

y=6√3

7 0

4 years ago

Help pls ty in advance

svetoff [14.1K]

$\bold{\huge{\underline{ Solution\: 2 }}}$

The name of the circle is IJKL
The name of central Angle
$\sf{\underline{= {\angle} IHJ }}$
The name of the secant = KL

${\bigstar}$ Circle :- It is a round figures, which has no end points.

${\bigstar}$ Central angle :- It the angle ,which lie in the middle of the circle.

Here, H is the mid point of the circle .So, Angle IHJ is the central angle.

${\bigstar}$ Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .

Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

$\bold{\huge{\underline{ Solution\: 3 }}}$

Semicircle = FGH and FIH
Minor Arc :- FG or GH
Major Arc :- FHG or GFH

${\bigstar}$ Semicircle :- Semicircle is nothing but the half of the circle.

Here, In second diagram 

FGH and FIH are acting as two semicircles which simulatineously forming one circle.

${\bigstar}$ Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.

Here, 

FG or GH are the minor arc of the given circle.

${\bigstar}$ Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.

Here, 

FHG or GFH is the major arc as it is larger than the semicircle of the given circle .

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2 years ago

Find the modal class interval.

photoshop1234 [79]

Answer: 24≤ a < 26

Step-by-step explanation:

The modal class interval is the class interval with the highest frequency, the highest frequency from the table is 8 , which belongs to the class interval 24≤ a < 26

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3 years ago