Uh, i think this one is "two people", even though a 16 inch pizza is, in my opinion, more than enough. sorry if incorrect.
Answer:
6 laps
Step-by-step explanation:
Each lap Jeffrey needs to run is one tenth of a mile he wants to run threee fifths of a mile how many laps does he need to run
One tenth of a mile = 1/0
Three fifths of a mile = 3/5
From the question:
1/10 mile = 1 lap
3/5 mile = x
Cross Multiply
1/10 mile × x = 3/5 mile × 1 lap
x = 3/5 mile × 1 lap/ 1/10 mile
x = 3/5 ÷ 1/10
x = 3/5 × 10/1
x = 6 laps
Therefore, for there fifths of a mile(3/5) he needs to run 6 laps
A 
B denotes to all common elements in both A and B
- Sample space=S={1,2,3,4,5,6,7,8,9,10}
So
2 is common
Hence
A $\cap$ B={2}
