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Ivenika [448]
3 years ago
5

Which of the following graphs represents the equation y=2x+2?

Mathematics
2 answers:
ivann1987 [24]3 years ago
3 0
The answer is B. Graph B
Viktor [21]3 years ago
3 0
The answer would be B.
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A cab company charges
andrew11 [14]

Answer:

29 miles

Step-by-step explanation:

$5 plus 29 miles

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3 years ago
Use the discriminant to determine the number of solutions for the quadratic equation.
Leno4ka [110]

Answer:

2 real solutions

Step-by-step explanation:

y = -x^2 + 3x + 5

First find the the discriminant:

using b² - 4(a)(b)

(3)²- 4(-1)(5)

=9+20

=29

since the discriminant is more than 0, there are 2 real solutions

7 0
3 years ago
B=(2x+3)(4x^2-6x+9)-2(4^3-1)
nexus9112 [7]
B = (2x+3)(4x^2-6x+9)-2(4^3-1)
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Hope it helps : )
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2 years ago
What is the square root of 79
andreev551 [17]
79 is a prime, so we cannot reduce it. \sqrt{79} =8.888194417315589
6 0
4 years ago
Read 2 more answers
Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

4 0
4 years ago
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