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sergij07 [2.7K]
2 years ago
6

1. Let the sample space represent all the values from 1 to 10. Let A = {1, 2, 8} and B = {2, 7}. What is the P(A ∩ B)?

Mathematics
2 answers:
AnnZ [28]2 years ago
7 0

A \cap B denotes to all common elements in both A and B

  • Sample space=S={1,2,3,4,5,6,7,8,9,10}

So

  • A={1,2,8}
  • B={2,7}

2 is common

Hence

A $\cap$ B={2}

Marat540 [252]2 years ago
6 0

Answer:

P(A ∩ B) = 1/10

Step-by-step explanation:

Given:

  • Sample space (S) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
  • A = {1, 2, 8}
  • B = {2, 7}

We can represent this information in a Venn diagram (see attachment 1).

As there are 10 equally likely outcomes (which must add up to 1), the probability of each outcome is 1/10.

Therefore, we can redraw the Venn diagram with the probabilities instead of the values (see attachment 2).

P(A ∩ B) means the probability of events A and B happening together, so it is the section of the diagram where events A and B overlap.

Therefore, P(A ∩ B) = 1/10

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Answer:

15.24% probability that at least 2 will still stand after 35 years

Step-by-step explanation:

To solve this question, we need to understand the binomial distribution and the exponential distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

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Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

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Probability of a single tower being standing after 35 years:

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Mean of 25 years, so m = 25, \mu = \frac{1}{25} = 0.04

We have to find P(X > 35)

P(X > 35) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-0.04*35} = 0.2466

What is the probability that at least 2 will still stand after 35 years?

Now binomial.

Each tower has a 0.2466 probability of being standing after 35 years, so p = 0.2466

3 towers, so n = 3

We have to find:

P(X \geq 2) = P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.2466)^{2}.(0.7534)^{1} = 0.1374

P(X = 3) = C_{3,3}.(0.2466)^{3}.(0.7534)^{0} = 0.0150

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.1374 + 0.0150 = 0.1524

15.24% probability that at least 2 will still stand after 35 years

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