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2 years ago

I need help with this please and thank you!

Mathematics

1 answer:

Vlad [161]2 years ago

6 0

Answer: 2x^2 -16t

25t -20

Step-by-step explanation:

Multiply the corresponding terms to find out which answer belongs in each box. For the top left box you would multiply 5t x 4t = 20t^2. For the top right multiply -4 x 4t = -16t. For bottom left box multiply 5t x 5 = 25t and for the bottom right box multiple -4 x 5 = -20.

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I need help with number 5

Tju [1.3M]

Answer:

B. BD = 9

Step-by-step explanation:

Simply set the 2 equations equal to each other (both are congruent due to perpendicular bisector):

6x + 3 = 3x = 6

3x + 3 = 6

3x = 3

x = 1

Then substitute 1 for <em>x</em> in BD

6(1) + 3

6 + 3

BD = 9

7 0

3 years ago

Read 2 more answers

(Y+9)x2=42 find the cross products

sveta [45]

2y+18=42
2y=24
y=12
Hope this helps!

8 0

3 years ago

Factor completely 36x^2 − 25.

sveticcg [70]

Hello there!

$( (2^2*3^2x^2) - 25) \\ \\ Factoring: \boxed{36x2-25} \\ \\ (PROOF): \\ \\ (A+B) * (A-B) = \\
 A2 - AB + BA - B2 = \\
 A2 - AB + AB - B2 = \\
 A2 - B2 \\ \\$

Your final answer would be (<span> (6x + 5) • (6x - 5)).

Your correct answer would be (option d).

I hope this helps you!</span>

4 0

3 years ago

Read 2 more answers

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,159 was collected on the sale of 1,339 ticket

ivolga24 [154]

Answer:

455 adult tickets
884 student tickets

Step-by-step explanation:

Let "a" represent the number of adult tickets sold. Then 1339-a is the number of student tickets sold. The revenue collected was ...

5a + 1(1339-a) = 3159

4a = 1820 . . . . . . subtract 1339, collect terms

a = 455 . . . . . . . . divide by 4; adult tickets sold

(1339-a) = 884 . . . . student tickets sold

455 adult tickets and 884 student tickets were sold.

5 0

3 years ago

A rectangle has an area of 171 square meters. Its width is ten meters less than the length. Find the measures of the length and

9966 [12]

Step-by-step explanation:

The area of a rectangle is 171 m²

Let l is the length and b is the width of the rectangle

It width is 10 m less than the length. So,

b = l-10 ...(1)

Area of a rectangle is given by :

$A=l\times b\\\\171=l(l-10)\\\\l^2-10l=171\\\\l^2-10l-171=0\\\\l^2-19l+9l-171=0\\\\\text{taking common together}\\\\l(l-19)+9(l-19)=0\\\\(l-9)(l-19)=0$

l = 9 m or l = 19 m

If l = 9 m,

b = 9-10 = -1 m (can't be possible)

If l = 19 m

b = 19-10 = 9 m

So, the length an the breadth of the rectangle is 19 m and 9 m respectively.

8 0

3 years ago