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3 years ago

Need help with number 3

Mathematics

2 answers:

Oxana [17]3 years ago

8 0

Class C because it has the most amount of money and more students than the others

Stells [14]3 years ago

4 0

Class thee answer is class cccc ok

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Please help! Ill mark brainliest if correct! help ASAP

amm1812

Answer:

Its 1,020

Hope u get it right!!!

U got this!!!!!!!!!!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

2/3b 6+7=-1 <br><br> What is the value of b?

ZanzabumX [31]

Answer:

i dont know sorry

Step-by-step explanation:

5 0

3 years ago

If ∠A and ∠B are complementary, find the value of x given that ∠A=3x-2 and ∠B=x+12

xxMikexx [17]

Answer:

x=20 degrees

Step-by-step explanation:

complementary means the angles equal 90 degrees

so ∠A+∠B=90 degrees

∠A=3x-2 and ∠B=x+12

so subsitute

(3x-2)+(x+12)=90

then solve for x

4x+10=90

4x=80

x=20 degrees is your answer

6 0

3 years ago

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

4 0

3 years ago

A 6 sided number cube is tossed. what is the probability of rolling a 6 or an odd number?

Veronika [31]

For any probability the formula is $P_{desired}=\frac{desired}{total}$ . In this case we have 4 desired outcomes (the odds, 1, 3 and 5, and also 6) out of 6 total sides, so our probability $P_{oddor6} =\frac{odd or 6}{total sides}=\frac{4}{6} = \frac{2}{3}$ .

Mutually exclusive means the events cant occur at the same time. In our case it is not possible to roll both a 6 and an odd number at the same time since 6 is even. Therefore the events ARE mutually exclusive.

Combine the two parts and C is the correct answer. <span />

3 0

4 years ago