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Novosadov [1.4K]

3 years ago

6

William works at a nearby electronics store. He makes a commission of 6% on everything he sells. If he sells a computer for $764

.00
, how much money does William make in commission?

1 answer:

Alex17521 [72]3 years ago

6 0

I believe that he makes $45.84.

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CONSTRUCTION Vance wants to have pictures

Sindrei [870]

He can have 4 pictures framed and is left with $22.

6 0

3 years ago

Find the equation of a circle that has a diameter with the endpoints given by the points A(-4,9) and B (- 2, - 3) )

Aleksandr-060686 [28]

The equation of the circle is $(x+3)^{2}+(y-3)^{2}=37$

Explanation:

Given that the endpoints of the circle are A(-4,9) and B(-2,-3)

We need to determine the equation of the circle.

<u>Center:</u>

The center of the circle can be determined using the midpoint formula,

$Center=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Substituting the coordinates A(-4,9) and B(-2,-3), we get,

$Center=(\frac{-4-2}{2},\frac{9-3}{2})$

$Center=(\frac{-6}{2},\frac{6}{2})$

$Center=(-3,3)$

Thus, the center of the circle is (-3,3)

<u>Radius:</u>

The radius of the circle can be determined using the distance formula,

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Substituting the center (-3,3) and the endpoint (-4,9), we get,

$r=\sqrt{\left(-4+3\right)^{2}+\left(9-3\right)^{2}}$

$r=\sqrt{\left(-1\right)^{2}+\left(6\right)^{2}}$

$r=\sqrt{1+36}$

$r=\sqrt{37}$

Thus, the radius of the circle is $\sqrt{37}$

<u>Equation of the circle:</u>

The standard form of the equation of the circle is given by

$(x-a)^{2}+(y-b)^{2}=r^{2}$

where (a,b) is the center and r is the radius.

Substituting the values, we have,

$(x+3)^{2}+(y-3)^{2}=(\sqrt{37})^{2}$

$(x+3)^{2}+(y-3)^{2}=37$

Thus, the equation of the circle is $(x+3)^{2}+(y-3)^{2}=37$

7 0

3 years ago

HELP ASAP with this question

mihalych1998 [28]

A, the student failed to distribute. In his step one, he got 3x + 2 =y, but it's actually 3x + 6 = y

I got this by distributing 3 to both x and 2, which is 3x and 6.

8 0

3 years ago

Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6

kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

$y=12x^3-5x\\\\ y=2x^2+x+6$

Step-by-step explanation:

Given : Equation $12x^3-5x=2x^2+x+6$

We have to construct a system of equations that can be used to find the roots of the equation $12x^3-5x=2x^2+x+6$

Consider the given equation $12x^3-5x=2x^2+x+6$

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation $12x^3-5x=2x^2+x+6$

becomes,

$12x^3-5x=y=2x^2+x+6$

Thus, The system of equation becomes

$y=12x^3-5x\\\\ y=2x^2+x+6$

Option (a) is correct.

8 0

3 years ago

Read 2 more answers

The formula for any geometric sequence is a n = a 1 · r n - 1 , where a n represents the value of the nth term, a 1 represents t

AfilCa [17]

Answer:

Step-by-step explanation:instead, try making the subscripts and superscripts stand out:

n-1

a = a * r

n n-1

Believe me, it's worth the extra work to do this!!

Given the sequence -3, -6, -12, -24, you can easily see that the first term,

a is -3. The common factor is 2. Note how (-3)*2=-6, and so on.

1

So, a = -3 and r=2.

1

So the formula for this geometric sequence is

n-1

a = -3*2

n

8 0

3 years ago

Read 2 more answers