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Assoli18 [71]
3 years ago
6

Thank you so much for solving this!

Mathematics
2 answers:
Eduardwww [97]3 years ago
7 0

Answer:

3. 6^9 / 6^-2

5. (6^3)^3

Step-by-step explanation:

What you do is solve for each of the expressions and each one that is less than 6^14 / 6^2 is your answer.

Let's start with what 6^14 / 6^2 equals:

<em>6^14 / 6^2 = 2,176,782,336</em>

Now lets start at the top and work our way down.

<em>6^15 x 6^-2 = 470,184,984,576    </em><u>This is bigger than 6^14 / 6^2 so this is not one of the answers.</u>

<em>6^8 / 6^-6 = 7.83641641 x10^10    </em><u>This is bigger than 6^14 / 6^2 so this is not one of the answers.</u>

<em>6^9 / 6^-2 = 362,797,056       </em><u>This is smaller than 6^14 / 6^2 so this is one of your answers.</u>

<em>6^16 x 6^-4 = 2,176,782,336    </em><u>This is the same as 6^14 / 6^2 so this is not one of the answers.</u>

<em>(6^3)^3 = 10,077,696        </em><u>This is smaller than 6^14 / 6^2 so this is one of your answers.</u>

3. 6^9 / 6^-2

5. (6^3)^3

These are your answers.

Gnoma [55]3 years ago
5 0

Hey there! Your answer should be  the first one and the second one. I do hope it was right. So sorry if I was wrong. Hope it helped! Your fellow Brainly user, GalaxyGamingKitty.

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17. Evaluate a. 6! b. 8P5 c. 12C4
Andreyy89
The factorial ! just means we multiply by every natural number less that the value so
6! =6×5×4×3×2×1= 720

for permutations we use the formula n!/(n-r)!
so we have 8!/(8-5)!=8!/3!=8×7×6×5×4

for combinations s we have n!/(n-r)!r!
so we have 12!/(12-4)!4!=12!/8!4!=12×11×10×9/4×3×2=11×10×9/2=99×5
7 0
3 years ago
The researcher is interested to know if policy A (new) is more effective than policy B (old). Frame the hypothesis and describe
vesna_86 [32]

<u>Answer:</u>

<u>Null hypothesis: Policy B remains more effective than policy A.</u>

<u>Alternate hypothesis: Policy A is more effective than policy B.</u>

<u>Step-by-step explanation:</u>

Remember, a hypothesis is a  usually tentative (temporary until tested) assumption about two variables– independent and the dependent variable.

We have two types of hypothesis errors:

1. A type I error occurs when the null hypothesis (H0) is wrongly rejected.

That is, rejecting the assumption that policy B remains more effective than policy A when it is <em>actually true.</em>

2. A type II error occurs when the null hypothesis H0, is not rejected when it is actually false. That is, accepting the assumption that policy B remains more effective than policy A when it is <em>actually false.</em>

3 0
3 years ago
Suppose a population is growing by 8% each year. How many years will it take the population to double?
Doss [256]

ANSWER

\text{9 years}

EXPLANATION

We want to find the number of years that it will take the population to double.

To do this, we have to apply the exponential growth function:

y=a(1+r)^t

where y = final value

a = initial value

r = rate of growth

t = time (in years)

For the population to double, it means that the final value must be 2 times the initial value:

y=2a

Substitute the given values into the function above:

\begin{gathered} 2a=a(1+\frac{8}{100})^t \\ \frac{2a}{a}=(1+0.08)^t=1.08^t \\ 2=1.08^t \end{gathered}

To solve further, convert the function from an exponential function to a logarithmic function as follows:

\log _{1.08}2=t

Solve for t:

\begin{gathered} \frac{\log _{10}2}{\log _{10}1.08}=t \\ \Rightarrow t=9\text{ years} \end{gathered}

It will take 9 years for the population to double.

4 0
11 months ago
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Img attached

\huge\mathfrak\colorbox{white}{}

7 0
1 year ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
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