24 is the numerical coefficient
1.06 is the base of the power with exponent t
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer:
False
Step-by-step explanation:
The same function input (the first number in the pair) cannot have two different outputs (the second number in the pair).
(6, 4) 4 is one output.
(6, -4) -4 is another output.
Answer: 123
Step-by-step explanation:
X = 2y + 7 ...............(1)
2x + 2y = 200 ........(2)
Substituting the expression for x in equation (1) into equation (2) gives
2(2y + 7) + 2y = 200 .....(3)
Equation (3) simplifies to
6y = 186
Therefore y = 31 feet.
Substituting the value for y into (1) gives
x = 69 feet.
