Solve the system of linear equations by substitution

2 answers:

7 0

There is the equal values method, so you can do:

x-4 = 4x-10 (remove x from both sides)
-4 = 3x -10 (add ten to both sides)
6 = 3x (devide by 3x)
2 = x

Check: (by plugging it into the equation)
y = 2-4 and y = 8-10
y = -2 and y = -2
that's matches so it is correct...
YOUR ANSWER IS:
(2, -2)

I hoped I helped sort things out, and have a great day!

Anit [1.1K]4 years ago

5 0

Y = x-4
y = 4x-10

Compare both the equations,
4x-10 = x-4
4x-x = 10-4
3x = 6
x = 6/3
x = 2

Now, substitute it in 1st equation,
y = 2-4 = -2

In short, Your Answer would be (2, -2)

Hope this helps!

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What expression is equivalent to 2^-3/2^-5?

mr_godi [17]

2^2 , or 4
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.

So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2

The new exponent is 2 because -3-(-5) is equal to 2.