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alexandr1967 [171]
3 years ago
12

Solve the system of linear equations by substitution

Mathematics
2 answers:
elena-s [515]3 years ago
7 0
There is the equal values method, so you can do:

x-4 = 4x-10 (remove x from both sides)
-4 = 3x -10 (add ten to both sides)
6 = 3x  (devide by 3x)
2 = x

Check: (by plugging it into the equation)
y = 2-4 and y = 8-10
y = -2 and y = -2
that's matches so it is correct...
 YOUR ANSWER IS:
(2, -2)

I hoped I helped sort things out, and have a great day!
Anit [1.1K]3 years ago
5 0
Y = x-4
y = 4x-10

Compare both the equations, 
4x-10 = x-4
4x-x = 10-4
3x = 6
x = 6/3
x = 2

Now, substitute it in 1st equation, 
y = 2-4 = -2

In short, Your Answer would be (2, -2)

Hope this helps!
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asic Geometric Shapes - Part 1 What is the value of x (3x +50) Enter your answer in the box. (6x - 10)
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1) From the picture, we see that we have two vertical angles:

\begin{gathered} A=(3x+50)^{\circ} \\ B=(6x-10)^{\circ} \end{gathered}

2) Now, because of the<em> "Vertical Angles Postulate"</em> from geometry, we know that angles A and B are equal, so equalling the angles and replacing by their expression from above, we get the following equation in terms of x:

\begin{gathered} A=B \\ 3x+50=6x-10 \end{gathered}

3) We must solve the last equation for x, doing that we find:

\begin{gathered} 3x+50=6x-10 \\ 50=6x-10-3x \\ 50+10=6x-3x \\ 60=3x \\ x=\frac{60}{3} \\ x=20 \end{gathered}

Steps to solve the equation

0) We have the equation:

3x+50=6x-10

1) We want all the terms with x on one side, and the other on the other one. So we pass the term +3x to the right as -3x:

50=6x-10-3x

2) Now we pass the term -10 to the left as +10:

50+10=6x-3x

3) We sum the terms on each side:

60=3x

4) We pass the 3 that multiplies the x on the right, dividing the 60 on the left:

x=\frac{60}{3}

5) Finally we make the division and we get:

x=20

Answer

x = 20

6 0
1 year ago
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