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3 years ago

What tools did the greeks use in geomatric constructions

Mathematics

2 answers:

gulaghasi [49]3 years ago

5 0

Answer:

compass or a straightedge.

Step-by-step explanation:

I think

Luba_88 [7]3 years ago

4 0

Answer:

straightedge and compass

Step-by-step explanation:

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Write the equation in slope-intercept form. y - 2 = 6 (x + 1)

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y=6x+8

Step-by-step explanation:

Write in slope-intercept form, y=mx+b.

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3 years ago

Pls help I will give brainliest . The answer choices are

Elan Coil [88]

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Step-by-step explanation:

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3 years ago

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4 years ago

I FREAKING NEED HELPPP!!!

Ratling [72]

Answer:

$\boxed{\begin{bmatrix} 3 & - 1 \\ - 3 & 4\end{bmatrix} = 12 - 3 = \boxed{9} }\\ \\ \boxed{\begin{bmatrix} -12 & - 1 \\ 12 & 5\end{bmatrix} = - 60- ( - 12) = \boxed{ - 48}} \\ \\ \boxed{\begin{bmatrix} 0& - 1 \\ 17 & 4\end{bmatrix} = 0 -( - 17 )= \boxed{17}} \\ \\\boxed{ \begin{bmatrix} 8& - 1 \\ - 4 & - 1\end{bmatrix} = - 8 - 4 = \boxed{ - 12} }\\ \\ \boxed{\begin{bmatrix} 2 & - 1 \\ 2 & - 1\end{bmatrix} = - 2 - ( - 2) = \boxed{0}} \\ \\ \boxed{ \begin{bmatrix} 1 & 0\\ 0 &1\end{bmatrix} = 1 - 0 = \boxed{1}}$

Step-by-step explanation:

$the \: determinant \: of \: a \: matrix : A \to\\If \: A =\begin{bmatrix} x & y \\ a & b \end{bmatrix} \: then : \\ its \: determinant \: is \: givn \: by \to \\ |A| = (b \times x) - (a \times y) \\ \boxed{|A| = bx - ax}$

♨Rage♨

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3 years ago

Simplify. Evaluate the numerical bases. 3^2 b^2 c^-4 *3^-1 b^-5 c^7

photoshop1234 [79]

Hope I can be of assistance!

$3^2b^2c^{-4}\cdot \:3^{-1}b^{-5}c^7 \ \textgreater \ \mathrm{Apply\:exponent\:rule}:\ \:a^b\cdot \:a^c=a^{b+c}$
$3^{-1}\cdot \:3^2=\:3^{2-1}=\:3^1=\:3 \ \textgreater \ 3b^{-5}b^2c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ b^{-5}b^2=\:b^{2-5}=\:b^{-3}$
$3b^{-3}c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ c^{-4}c^7=\:c^{-4+7}=\:c^3$
$3b^{-3}c^3$

$\mathrm{Apply\:exponent\:rule}: \:a^{-b}=\frac{1}{a^b} \ \textgreater \ b^{-3}=\frac{1}{b^3} \ \textgreater \ 3\cdot \frac{1}{b^3}c^3$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{1\cdot \:3c^3}{b^3}$

Finally
$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{3c^3}{b^3}$

Hope this helps!

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4 years ago