What is the solution tonthe inequality of -9×-15<3=
1 answer:
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30 ounces of the coffee John likes consists of
ounces of water
ounces of cocoa
To this mixture we're adding ounces of water, so that the new mix has a total volume of
ounces and matches the composition of the coffee Lily likes. This means it would consist of
ounces of water
ounces of cocoa (same amount of cocoa as before because pure water is being added)
Solve for :
###
Just to confirm: the new mixture consists of
ounces of water
ounces of cocoa
giving a total volume of ounces of coffee, and
, as required.
The answer is: " 11 " .
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→ " x = 11 " .
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Explanation:
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Set up the ratio/ proportion as a fraction:
6 cm / 48 cm = 5 cm / (3x + 7) ;
→ The "cm" units cancel out; since: "cm/cm = 1 " ;
→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;
→ Rewrite as:
;
Now, we can "cross-multiply" :
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<u>Note</u>:
; 
;
{b
; d } .
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As such:
1 * (3x + 7) = 8 * 5 ;
→ 3x + 7 = 40 ;
Subtract "7" from each side of the equation:
→ 3x + 7 − 7 = 40 <span>− 7 ;
</span>
to get:
→ 3x = 33 ;
Now, divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 33 / 3 ;
to get:
____________________________________________________
→ " x = 11 " .
____________________________________________________
→ The answer is: " 11 " .
____________________________________________________
____________________________________________________
→ " x = 11 " .
____________________________________________________
Explanation:
____________________________________________________
Set up the ratio/ proportion as a fraction:
6 cm / 48 cm = 5 cm / (3x + 7) ;
→ The "cm" units cancel out; since: "cm/cm = 1 " ;
→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;
→ Rewrite as:
Now, we can "cross-multiply" :
__________________________________________________
<u>Note</u>:
{b
__________________________________________________
As such:
1 * (3x + 7) = 8 * 5 ;
→ 3x + 7 = 40 ;
Subtract "7" from each side of the equation:
→ 3x + 7 − 7 = 40 <span>− 7 ;
</span>
to get:
→ 3x = 33 ;
Now, divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 33 / 3 ;
to get:
____________________________________________________
→ " x = 11 " .
____________________________________________________
→ The answer is: " 11 " .
____________________________________________________