All categories

3 years ago

Which could be the missing data item for the given set of data if the median of the complete data set is 50?

2 answers:

6 0

Find the median of this data
21+23+60+60+50+54+54+59+26+15+43+15=480/ 12 = 40
Now the median should be 50 so take 50 - 40 = 10

The missing number from the data is 10

ioda3 years ago

3 0

Mostly likely missing mum is Thais an dog queston

You might be interested in

Hey please answer soon i need this done soon! 20points!!!

Zepler [3.9K]

Answer:

<h3>consistent independent</h3>

<h2>Explanation:-</h2><h3>The system of linear equations {3x−y=2y=3x+2 describes <em><u>consistent </u></em><em><u>independent </u></em><em><u>.</u></em></h3>

<h3>Hope it is helpful to you </h3><h3>stay safe healthy and happy ☺️</h3>

4 0

2 years ago

John, sally, Natalie would all like to save some money. John decides that it would be best to save money in a jar in his closet

stiv31 [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

$y=mx+b$

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

$y=100x+300$

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

$A=6,000(1.07)^{t}$

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

Read 2 more answers

John received $0.76 change from a purchase in the drugstore. if he received eight coins, and five of the coins are the same deno

Aliun [14]

<span>5 nickels , 2 quarters, and 1 pennies = 8 coins.</span>

<span> he received 2 quarters</span>

5 0

3 years ago

Monica walks 2 miles each day Monday through Friday. She walks 3 miles on Saturday. She does not walk on Sunday. Monica calculat

tekilochka [14]

Lets calculate how much she walks each weeks and then we multiply that by the number of weeks.
weekWalk = 5(2) + 3 = 10 + 3 = 13
therefore, she walks 13 miles per week, if she walked for 29 weeks then we have:
total walked =(29)(13) = 377
so she walked 377 miles total, so her original estimate is not reasonable

5 0

2 years ago

Brent has two barcode printing machines. Each machine can print 25 barcodes per minute. On day 1, only the first machine was use

Sonja [21]

I think it would be 95 + 25x + 25y

8 0

3 years ago

Read 2 more answers