P(most favorable outcome) = 1 -(0.03 +0.16 -0.01) = 0.82
_____
"repair fails" includes the "infection and failure" case, as does "infection". By adding the probability of "repair fails" and "infection", we count the "infection and failure" case twice. So, we have to subtract the probability of "infection and failure" from the sum of "repaire fails" and "infection" in order to count each bad outcome only once.
The probability of a good outcome is the complement of the probability of a bad outcome.
Clearly, alternative B
y = 0.01x + 7.5
y = (0.01)*5000 + 7,5
y = 50 + 7.5
y = 57.50
<h2>Evaluating Composite Functions</h2><h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
We can write how 
will be defined but that's too much work and it's only useful when we are evaluating with many inputs.
First let's solve for 
first. As you read through this answer, you'll get the idea of what I'm doing.
Given:
Solving for :
Now we can solve for 
, since 
, 
.
Given:
Solving for 
:
Now we are can solve for 
. By now you should get the idea why 
.
Given:
Solving for :
<span>a whole number; a number that is not a fraction.</span>
