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deff fn [24]
3 years ago
14

2y^2/y-7 - y^2+49/y-7

Mathematics
1 answer:
Anika [276]3 years ago
8 0

Answer:

y+7

Step-by-step explanation:

2y^2/y-7-y^2-49/y-7

=2y^2-y^2-49/y-7

=y^2-49/y-7

=(y+7)(y-7)/y-7

=y+7

Note:If you didn't understand just comment I will solve on paper and send the picture.

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Given that sine of theta = 21/29, what is the value of cosine of theta, for 0° < theta < 90°?
fenix001 [56]

If the value of θ is 46.4°. Then the value of the cosine of θ will be 20/29.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The value of sine of θ is 21/29.

Then the value of θ will be

sin θ = 21/29

     θ = sin⁻¹(21 / 29)

     θ = 46.4°

Then the value of the cosine of θ will be

cos θ = cos 46.4°

cos θ = 20/29

More about the trigonometry link is given below.

brainly.com/question/22698523

#SPJ1

7 0
2 years ago
PLEASE HELP!!!!
Katena32 [7]

Answer:

C

Step-by-step explanation:

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