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3 years ago

Which of the following is not a characteristic of term life insurance?

Mathematics

1 answer:

mariarad [96]3 years ago

3 0

Answer:

D-Ability to access cash value

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Help me with this question please.

Nadya [2.5K]

19:1 = 19:1

38:2 = 19:1

57:3 = 19:1

So, the constant is 19.

7 0

3 years ago

In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?

Sophie [7]

Answer: 6π

<u>Step-by-step explanation:</u>

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

$A=\pi r^2\bigg(\dfrac{\theta}{360^o}\bigg)$

Given: r = 6, Ф = 60°

$A=\pi (6)^2\bigg(\dfrac{60^o}{360^o}\bigg)\\\\\\.\quad =\pi (6)^2\bigg(\dfrac{1}{6}\bigg)\\\\\\.\quad =6\pi$

3 0

3 years ago

Amalia used 8 lemons to make a picture of lemonade that served six people. How many lemons would she need to make enough lemonad

11111nata11111 [884]

28 lemons is the answer to your question

8 0

3 years ago

Choose the multiples of 2.

IgorLugansk [536]

B)
2x6= 12
2x7= 14
2x8= 16
2x8= 18

3 0

3 years ago

Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me

Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

$V= \pi r^2 h$

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

$dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr$

So finding the partial derivatives we get

$dV =\pi r^2 dh + \pi 2r h dr$

$dV =\pi r^2 dh + 2\pi r h dr$

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

$dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)$

That give us

$V= 28 \pi \, cm^3$

Or in decimal value

$\boxed{dV= 87.96 \, cm^3}$

Thus the volume of metal in the can is 87.96 cubic cm.

6 0

4 years ago