A. Sugar And Brown Sugar (For Cookies)
B. No.
C 1/2 Cup (INGREDIENT) And 1/8 Cup (INGREDIENT)
Answer:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Answer:
We can reject the hypothesis at the 0.05 significance level.
Step-by-step explanation:
given that an urn contains a very large number of marbles of four different colors: red, orange, yellow, and green. A sample of 12 marbles drawn at random from the urn revealed 2 red, 5 orange, 4 yellow, and 1 green marble.
H0: All colours are equally likely
Ha: atleast two colours are not equally likely
(Two tailed chi square test at 5% significance level)
color Red Orange Yellow Green total
Observed O 2 5 4 1 12
Expected E 3 3 3 3 12
(O-E)^2/E 0.3333 5.3333 0.3333 5.3333 11.3333
chi square = 11.3333
df =3
p value = 0.010055
Since p < 0.05 we reject H0
We can reject the hypothesis at the 0.05 significance level.