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Alenkinab [10]
4 years ago
11

you've been contracted to wallpaper a wall 10 ft wide and 12 ft High with a square window with 3-foot sides. How many square fee

t of wallpaper do you need to cover the wall if you were to exclude the opening for the window? _Square feet

Mathematics
2 answers:
bogdanovich [222]4 years ago
5 0

Find the total area of the wall, including the window area:  (10 ft)(12 ft) = 120 ft^2.

Next, find the window area:  (3 ft)^2 = 9 ft^2

and, finally, subtract the window area from the total wall area:  (120-9) ft^2, or

111 ft^2.  The total amount of wallpaper needed, with zero waste, is 111 ft^2.

ELEN [110]4 years ago
3 0
111 square ft would be the answer
You might be interested in
How to write unit form for (2 tens 1 one) x 10
poizon [28]
Numbers are arranged by their place values. Place values give a quantity of value to a certain digit in a number. Given a number, the rightmost number is the ones place, followed by the tens place, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, hundred millions, as so on and so forth. The place value of a certain digit is 10 times bigger than its adjacent digit to the right.

So for this problem, all you have to do is multiply the number of units of each place value, then multiple them all by 10.

(2(10) + 1(1))×10
21 × 10 = 210

Therefore, the number is equivalent and written as 210.
3 0
4 years ago
AWARDING EXTRA POINTSWhat is the distance between point A (-3, -2) and Point B (4, -7)?
kenny6666 [7]

Answer:

Hi there!

Your answer is:

<em>8</em><em>.</em><em>6</em><em> </em><em>units</em>

Step-by-step explanation:

The distance formula is

√ ( (x2-x1)^2 + (y2-y1)^2 )

In your points:

A (-3, -2)

-3 is x1

-2 is y1

B (4, -7)

4 is x2

-7 is y2

Plug in to distance formula

√ ( 4-( -3))^2 + ( -7 - (-2))^2

√ (4+3)^2 + (-7+2)^2

√ (7^2) + ( -5)^2

√ 49 + 25

√ 74

This equals roughly 8.6 units!

4 0
3 years ago
A math teacher gets a starting salary of $30,000. IF she gets a 1.5% increase in salary each year, what will her total income be
kolezko [41]
No it is not base e.  It is 1.015.

An increase of 1.5 % =  1.015 

Year            1,             2,                       3,.........................., 30.
               30000, 3000(1.015),  30000(1.015)²,........... 30000(1.015)²⁹

Her Total Income is sum over the thirty 30 year period:

Sn =  a(r^n  - 1) / (r - 1);                a = 30000,  r = 1.015,  n = 30

Sn =  30000 ( 1.015^30  -  1) / (1.015 - 1)

      =  30000 (1.56308022 - 1) / (0.015) =  1126160.44

Total =  $ 1 126 160.44

5 0
3 years ago
Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat
SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

<u><em>Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes</em></u>

Reasoning in the same way:

<u><em>Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes</em></u>

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

<u><em>3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes</em></u>

5 0
4 years ago
The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si
OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!

a) The probability that exactly 3 arrivals occur during a particular hour is:

P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938

c) In this case, t=0.25, so we recalculate the parameter as:

\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

E(x)=\lambda=1.5

3 0
3 years ago
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