Area of wall = l×b
Length = 5m
Breadth = 20m
Area = 5×20
=100m²
Area of flex = side×side
= 2×2
= 4m²
Now no of flex that can be fitted = 100/4
= 25 flex
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Answer:
Therefore,
The length of the sides of the squares is

Step-by-step explanation:
Let "x" be the length of Cut Square,
As the tin size(Dimension) is
20 cm × 50 cm
So the size(Dimension) of box will be
(20 - 2x) × (50 - 2x)
Length = 50 - 2x
Width = 20 - 2x
Area of base of box = 216 cm²
To Find:
x = ?
Solution:
Area of Rectangular field is given by

Substituting the values we get

Applying Distributive property we get


Dividing throughout by 4 we get

On Factorizing we get

As x cannot be 28 because tin size is 20 cm × 50 cm i.e longer than 20
Therefore,

Therefore,
The length of the sides of the squares is

X= -3
2x+3+7x=-24
9x+3= -24
9x= -27
x= -3
Answer:
b
Step-by-step explanation:
took the test i got bj : fz wf