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3 years ago

Solve the system of equations x+4y=15 2x-y=-15

Mathematics

1 answer:

Lady_Fox [76]3 years ago

7 0

x+4y=15 2x-y=-15

We have to make x neg.

-2(x) + 4y (-2)= -2(15)

-2x-8y=-30

2x-y=-15

-9y= -45

Solve for y

Y=-45/-9

Y = 5

Substitute your y answer into one original equation to find x .

x+4y=15

X+4(5)=15

X+20=15

X=15-20

X= -5

Answer is (-5,5)

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What is the answer for number 8 and pls give step by step

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Answer:

Trapezoid 1 (left side):

Base 1 = 2

Base 2 = 5

Trapezoid 2 (right side):

Base 1 = 6

Base 2 = 8

Step-by-step explanation:

<u>1st trapezoid:</u>

b_1 = x

b_2 = x + 3

h = 4

Hence, area (from formula) would be:

$A=\frac{h}{2}(b_1+b_2)\\A=\frac{4}{2}(x+x+3)\\A=2(2x+3)\\A=4x+6$

<u>2nd trapezoid:</u>

b_1 = 3x

b_2 = 4x

h = 2

Putting into formula, we get:

$A=\frac{h}{2}(b_1+b_2)\\A=\frac{2}{2}(3x+4x)\\A=1(7x)\\A=7x$

Let's equate both equations for area and find x first:

$4x+6=7x\\6=7x-4x\\6=3x\\x=\frac{6}{3}\\x=2$

We can plug in 2 into x and find length of each base of each trapezoid.

Trapezoid 1 (left side):

Base 1 = x = 2

Base 2 = x + 3 = 2 + 3 = 5

Trapezoid 2 (right side):

Base 1 = 3x = 3(2) = 6

Base 2 = 4x = 4(2) = 8

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