PLEASE HELP ASAP!! Thank you!

How many centimeters are in 15 meters?

Dmitry [639]

Answer:

The answer is d.) 1,500centimeters

Step-by-step explanation:

8 0

3 years ago

51. (08.02 MC) Box A has a volume of 48 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were double

Vanyuwa [196]

Answer:

384 m³

Step-by-step explanation:

Let the dimension of box a be l,b, and h.

ATQ,

lbh = 48 .....(1)

If we double the dimension of box A, we get box B whose new dimensions will be 2l,2b and 2h.

Let V be the volume of box B.

V = (2l)(2b)(2h)

V = 8(lbh)

= 8(48) [from equation (1)]

= 384 m³

Hence, the volume of the box B is 384 m³.

7 0

3 years ago

Grace and her friends are playing a game that uses two dice. Each die is a tetrahedron – a four‐sided shape with each side an eq

lesya [120]

I need more information

7 0

2 years ago

Write an equation to describe the relationship in each table.

GuDViN [60]

Answer:

First table: 2x+1=y

Second table: 3x+2=y

Step-by-step explanation:

It was really just testing it out, checking to see if an equation worked for one row, then try in the next. Its hard to explain, but its really just guess and check ;D

I hope this helps!

4 0

2 years ago

Read 2 more answers

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The

TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 salmon, to grocery stores in cartons of 16 salmon, and to discount outlet stores in pallets of 64 salmon. To forecast costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts (a) and (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: $\frac{s.d}{\sqrt{u}}$

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{9}}$

$= \frac{3}{3} = 1$

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{16}}$

$= \frac{3}{4} = 0.75$

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{64}}$

$= \frac{3}{8} = 0.375$

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

5 0

3 years ago