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3 years ago

Pls help me I rlly don’t get it :(

Mathematics

1 answer:

zhenek [66]3 years ago

8 0

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

Let's start with #12. The hypotenuse is 18. The side adjacent to ∠B is 6. Since we have the adjacent side and hypotenuse, we should use cosine.

cos B = 6/18

Solving for B:

B = cos⁻¹(6/18)

Using a calculator:

B ≈ 70.5°

Now let's do #14. The side adjacent to ∠B is 19, and the side opposite of ∠B is 22. Since we have the adjacent side and opposite side, we should use tangent.

tan B = 22/19

Solving for B:

B = tan⁻¹(22/19)

Using a calculator:

B ≈ 49.2°

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An unusually wet spring has caused the size of a mosquito population in some city to increase by 8% each day. If an estimated

tatyana61 [14]

Answer:

The number of mosquitoes that will inhabit the city on May 25 is 4,471,200.

Step-by-step explanation:

Note: This question is not complete as some important figures and points are omitted. The complete question is therefore provided before answering the question as follows:

An unusually wet spring has caused the size of a mosquito population in some city to increase by 8% each day. If an estimated 180,000 mosquitoes are in the city on May 12, find how many mosquitoes will inhabit the city on May 25. Use y= 180,000(1.08)x where x is number of days since May 2.

The explanation to the answer is now given as follows:

Given;

y = 180,000(1.08)x = 180,000 * 1.08 * x .................... (1)

Where;

y = Number of mosquitoes that will inhabit the city on May 25 = ?

x = Number of days since May 2 = 25 - 2 = 23

Substituting for x = 23 into equation (1), we have:

y = 180,000 * 1.08 * 23

y = 4,471,200

Therefore, the number of mosquitoes that will inhabit the city on May 25 is 4,471,200.

3 0

2 years ago

A Local group claims that the police issue more than 60 speeding tickets a day in thire area. To prove their point, they randoml

MissTica

Answer:

The group's claim is not supported at 1% significance level.

Step-by-step explanation:

given that a local group claims that the police issue more than 60 speeding tickets a day in thire area

The data they collected for 2 weeks is given below:

70 48 41 68 69 55 70

57 60 83 32 60 72 58

$\bar x = 60.2\\s = 12.9\\n=14$

Std error of mean = $\frac{12.9}{\sqrt{14} } \\=3.4477$

$H_0: \bar x=60\\H_a: \bar x >60$

(Right tailed test at 1% significance level)

Mean difference = 0.10

Test statistic t with df 13 = mean difference/std error

= 0.029

p value = 0.4886

Since p >0.01, we accept null hypothesis

The group's claim is not supported at 1% significance level.

7 0

3 years ago

What is the factored form of the expression?<br><br> d^2 = 36d + 324

Veseljchak [2.6K]

Answer:

$(x-43.45)(x+7.45)=0$

Step-by-step explanation:

We have the quadratic equation $d^{2}=36d+324$ i.e. $d^{2}-36d-324=0$

As, the roots of the quadratic equation $ax^{2}+bx+c=0$ are given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ .

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ , we get,

$x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}$

i.e. $x=\frac{36\pm \sqrt{1296+1296}}{2}$

i.e. $x=\frac{36\pm \sqrt{2592}}{2}$

i.e. $x=\frac{36\pm 50.9}{2}$

i.e. $x=\frac{36+50.9}{2}$ and $x=\frac{36-50.9}{2}$

i.e. $x=\frac{86.9}{2}$ and $x=\frac{-14.9}{2}$

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be $(x-43.45)(x+7.45)=0$

3 0

3 years ago

PLZZ HELP ASAP ILL MAKE U BRAINLIEST

user100 [1]

Translation right down c=

4 0

3 years ago

Read 2 more answers

A comparison of students’ High School GPA and Freshman Year GPA was made. The results were: First screenshot

Mkey [24]

Answer:

freshman are smarter

Step-by-step explanation:

4 0

2 years ago