Answer:
(For the first two questions I do believe that you will need a protractor to calculate the angles.)
15) 
measures out to -70° in order to display that the angle would be in quadrant IV (the bottom right quadrant.)
The first image attached shows where the angle should be located.
16) 
is equal to 60° (the line you draw will be in quadrant 1 (the top right quadrant))
17) 350° is 
or 6.11 (the answer depends on the format the professor wants.)
18) 240° is 
radians or -4.19 (I am rounding to the nearest hundredths place the unsimplified answer is −4.18879020...)
T\The answer would be 3 6/10, or 3.6.
Step-by-step explanation:
ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.
OC is now a median for ABC splitting the angle at C and AB in half.
so, we have 2 right-angled triangles : OAC and OBC.
the half-angles at C are 42/2 = 21°.
the angles at A and B are 90°.
and the half-angles at O are 180 - 90 - 21 = 69°.
remember that the sum of all angles in a triangle must always be 180°.
AB are the heights of both of these triangles.
the single height is sin(69)×7 = 6.535062985... cm
and so,
AB = 2× height = 13.07012597... cm.
Your answer would be 4 over x to the sixth which would look like this
4
_
x^6
the ^ symbol means it’s an exponent
