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zalisa [80]
3 years ago
9

What is the answer for 7÷ 4/5

Mathematics
2 answers:
Strike441 [17]3 years ago
7 0

Answer:

7 ÷ 4/5 is 8.75 as a decimal or 8 3/4 as a fraction

MrMuchimi3 years ago
4 0

Answer:

8¾

Step-by-step explanation:

7÷ 4/5

7 × 5/4

= 35/4

= 8¾

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36 is the answer, hope this helps.

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8^2 /2+5(15-7)

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</span></span></span><span>=<span><span><span>(3)</span><span>(<span>−4</span>)</span></span>+<span>4<span>(<span>4−9</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span>4<span>(<span>4−9</span>)
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</span></span></span></span><span>=<span><span>−12</span>+<span>−20
</span></span></span><span>=<span>−32

</span></span><span><span>10<span>(<span>9−18</span>)</span></span>−<span>32
</span></span><span>=<span><span><span>(10)</span><span>(<span>−9</span>)</span></span>−<span>32
</span></span></span><span>=<span><span>−90</span>−<span>32
</span></span></span><span>=<span><span>−90</span>−9
</span></span><span>=<span>−<span>99

</span></span></span><span><span>−<span>12<span>(<span>5−7</span>)</span></span></span>−<span>10<span>(<span>2−5</span>)
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6 0
3 years ago
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The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50. He selects 4 of the 50 re
Mariana [72]

Answer:

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

Step-by-step explanation:

Sets are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Lots of 50 means that N = 50

5 are defective, which means that k = 5

4 are selected, which means that n = 4

Find the probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,50,4,5) = \frac{C_{5,2}*C_{45,2}}{C_{50,4}} = 0.0430

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

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Answer:

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