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4 years ago

I need help on this one please

Mathematics

2 answers:

Ann [662]4 years ago

5 0

6: 12,18,24,30,36,42
8: 16,24,32,40,48,56

the smallest dollar amount would be 24, so the both sold $24 worth of cookies

Ahmad sold 3 boxes of cookies
tammy sold 4 boxes of cookies

Jobisdone [24]4 years ago

3 0

The multiples for 6 : 6, 12, 18, 24, 30,36, 42, 48

The multiples for 8 : 8, 16, 24, 32, 40, 48, 56, 64

Hope this helps

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You are dealt one card from 52 card deck. Find the possibility that you are dealt a heart or a picture card

PIT_PIT [208]

Answer:

Step-by-step explanation:

Since we have 13 heart card then

p(heart) = 13/52

Since we have 12 picture card then

p(picture) = 12/52

Since we have 3 heart and picture (at the same time) card then

p(heart∩picture) = 3/52

finally,

the possibility that you are dealt a heart or a picture card = p(heart or picture)

p(heart or picture) = 13/52 + 12/52 - 3/52 = 22/52

7 0

4 years ago

Isoke is solving the quadratic equation by completing the square.10x2 + 40x – 13 = 0 10x2 + 40x = 13 A(x2 + 4x) = 13What is the

Elina [12.6K]

we have

$10x^{2} + 40x - 13 = 0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$10x^{2} + 40x =13$

Factor the leading coefficient

$10(x^{2} + 4x) =13$ ----------> the value of A is $10$

Complete the square. Remember to balance the equation by adding the same constants to each side

$10(x^{2} + 4x+4) =13+40$

$10(x^{2} + 4x+4) =53$

Rewrite as perfect squares

$10(x+2)^{2} =53$

$10(x+2)^{2} =53 \\ (x+2)^{2} =\frac{53}{10} \\ \\ x+2=(+/-)\sqrt{\frac{53}{10}} \\ \\ x1=-2+\sqrt{\frac{53}{10}}\\ \\ x2=-2-\sqrt{\frac{53}{10}}$

therefore

the answer is

the value of A is $10$

3 0

3 years ago

Read 2 more answers

Miley has $40 in her savings account. She plans to save $25 per week from now on. Select the equation that models the total amou

Semmy [17]

A. S = 25w + 40

Because 25 x w = how much she saved

Then + 40 = how much she will have after saving up

5 0

3 years ago

plz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help

Volgvan

Answer:

the answer should be 9

Step-by-step explanation:

$(256 * 3^{-5} * 6^{0} )^{-2} * (\frac{3^{-2}}{2^{3}} )^{4} * 2^{28}$

$(256*\frac{1}{3^{5}} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(256*\frac{1}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(\frac{256}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(\frac{256}{243})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(\frac{243}{256})^{2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$\frac{59049}{65536}*(\frac{1}{2^{3}*3^{2}})^{4}*2^{28}$

$\frac{59049}{65536}*(\frac{1}{8*9})^{4}*2^{28}$

$\frac{59049}{65536}*(\frac{1}{72})^{4}*2^{28}$

$\frac{59049}{65536}*\frac{1}{26873856}*2^{28}$

$\frac{9}{65536}*\frac{1}{4096}*2^{28}$

$\frac{9}{65536*4096}*2^{28}$

$\frac{9}{268435456}*268435456$

$9$

6 0

3 years ago

Read 2 more answers

5(-3y+3z)-3(-5z-y) simplified

Virty [35]

Answer:

5-(-3y+3z)-3(-5z-y) = 6y+12z+5

Step-by-step explanation:

5−(−3y+3z)−3(−5z−y)

Distribute:

=5+3y+−3z+(−3)(−5z)+(−3)(−y)

=5+3y+−3z+15z+3y

Combine Like Terms:

=5+3y+−3z+15z+3y

=(3y+3y)+(−3z+15z)+(5)

=6y+12z+5

8 0

3 years ago