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lilavasa [31]
3 years ago
11

You invest $2,000.00 at a rate of 4% APR for a 3 months. How much interest did you earn?

Mathematics
2 answers:
Firlakuza [10]3 years ago
7 0

Answer:

1.a

2.c

3.c

4.b

100% brainless please

Naya [18.7K]3 years ago
4 0
<span>1) If you invest $2,000.00 at a rate of 4% APR for 3 months and the interest is compounded monthly then in 3 months.It will be worth $2,020.07.
So subtracting $2,000 from $ 2,020.07
we get.
<span>$20.07

2) </span></span><span>I = Prt </span>
<span>I = 4,000 * 0.05 </span>
<span>I = $200 

</span><span>200 / 10 = 20 hours of work</span>
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Answer:

The population standard deviation is not known.

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Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus 11 - 1 = 10.

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

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  • The area to the left of the upper end of the interval shall be 0.05 + 0.90 = 0.95.

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

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t \approx 1.812.

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}},

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  • s_{n-1} is the unbiased estimate for the standard deviation, and
  • n is the sample size.

For this confidence interval:

  • t \approx 1.812,
  • s_{n-1} = 14, and
  • n = 11.

Hence the width of the 90% confidence interval is

\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65.

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

(38.3, 53.7).

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