Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probab
2 answers:
Answer:
Number of times would Lewis be expected to roll a multiple of 3 = 75
Step-by-step explanation:
Multiples of 3 in 1 to 10 are 3,6 and 9
So we are having 3 multiples of 3 in 1-10
Probability of an event is the ratio of number of favorable outcome to the total number of outcomes.
Probability to roll a multiple of 3
Total number of rolling = 250
Based on the theoretical probability, number of times would Lewis be expected to roll a multiple of 3 = Total number of rolling x Probability to roll a multiple of 3
Number of times would Lewis be expected to roll a multiple of 3
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Answer: x = -4, y = 0.5, z = 5 +t
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The line L whose direction is parallel to vector V a passes through point A
is parametrized
Where t, is a real number, and is a any point on line L.
In this case the direction is that of the z-axis , so V = (0, 0, 1)
A is the midpoint between points B = (0, -4, 9) and C=(-8, 5, 1)
The midpoint is A = (B + C)/2 = (-4, 0.5, 5)
Then the line is:
The equations for each coordinate are: