Question

Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probability, how many times would Lewis be expected to roll a multiple of 3?

Answer 1

Answer:

Number of times would Lewis be expected to roll a multiple of 3 = 75

Step-by-step explanation:

Multiples of 3 in 1 to 10 are 3,6 and 9

So we are having 3 multiples of 3 in 1-10

Probability of an event is the ratio of number of favorable outcome to the total number of outcomes.

Probability to roll a multiple of 3 $=\frac{3}{10}$

Total number of rolling = 250

Based on the theoretical probability, number of times would Lewis be expected to roll a multiple of 3 = Total number of rolling x Probability to roll a multiple of 3

Number of times would Lewis be expected to roll a multiple of 3 $=250\times \frac{3}{10}=75$

Answer 2

75 time because the proabablity of rolling any number each time is 1/10 so 250/10=25 the mutiples of 3 in 1-10 are 3,6,9 so 3*25 =75 tmes