Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probab
2 answers:
Answer:
Number of times would Lewis be expected to roll a multiple of 3 = 75
Step-by-step explanation:
Multiples of 3 in 1 to 10 are 3,6 and 9
So we are having 3 multiples of 3 in 1-10
Probability of an event is the ratio of number of favorable outcome to the total number of outcomes.
Probability to roll a multiple of 3
Total number of rolling = 250
Based on the theoretical probability, number of times would Lewis be expected to roll a multiple of 3 = Total number of rolling x Probability to roll a multiple of 3
Number of times would Lewis be expected to roll a multiple of 3
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Answer:
No, they are not equal
Step-by-step explanation:
If x = 1
4(5+x) = 4(5+1) = 4 x 6 = 24
(5+4) + x = 9 +1 = 10
2410
Option D:
The set is {-2, -1, 0, 1, 2, 3, 4}.
Solution:
Given set:
Z means integer values.
Integer means set of positive and negative values including zero.
This means x lies between -2 and 4.
- If x strictly less than -2 and greater than 4 means you don't have to include -2 and 4.
- But here x less than or equal to -2 and greater than or equal to 4, so you have to include -2 and 4.
The integers are -2, -1, 0, 1, 2, 3 and 4.
So, x belongs to the set {-2, -1, 0, 1, 2, 3, 4}
Hence the given set is defined by the set {-2, -1, 0, 1, 2, 3, 4}.
Option D is the correct answer.