Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probab
2 answers:
Answer:
Number of times would Lewis be expected to roll a multiple of 3 = 75
Step-by-step explanation:
Multiples of 3 in 1 to 10 are 3,6 and 9
So we are having 3 multiples of 3 in 1-10
Probability of an event is the ratio of number of favorable outcome to the total number of outcomes.
Probability to roll a multiple of 3
Total number of rolling = 250
Based on the theoretical probability, number of times would Lewis be expected to roll a multiple of 3 = Total number of rolling x Probability to roll a multiple of 3
Number of times would Lewis be expected to roll a multiple of 3
You might be interested in
You would expand becausee it isn't equal to anything
(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one
so
for the 3rd power
a=x
b=3
=
(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one
so
for the 3rd power
a=x
b=3