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tatyana61 [14]
3 years ago
8

Is a centiliter greater than a milliliter

Mathematics
1 answer:
vekshin13 years ago
7 0
<u><em>Yes </em></u>they are.
Foot
Inches
Centimeters
Millimeters
Hope this helps.
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Jasmine needs to reduce the height of a picture from 5 inches to 2 inches so it will fit in the yearbook. What percentage of the
Usimov [2.4K]
Jasmine is reducing the height of the yearbook picture from 5 inches to 2 inches and we are trying to find the percentage of the original height that is the new height.

The original height was 5 inches and the new height is 2 inches.

new/original = 2/5

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0.4 = 40%

Thus, the new height is 40% of the original height.

6 0
3 years ago
I need help with math
jekas [21]

Hello there!

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7 0
4 years ago
Cans of soda cost $0.30 in a certain vending machine. What is the expected value and variance of daily revenue from that machine
fgiga [73]

Answer:

The expected revenue is $37.50 and the variance of the revenue is $4.50.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of cans of soda sold per day.

The expected number of cans sold per day is:

E (X) = 125

The variance of the number of cans sold per day is:

V (X) = 50

The cost of one can of soda is:

Cost of <em>X</em> = $0.30

The formula to compute the expected revenue is:

E(R)=Cost\ of\ X\times E(X)

The formula to compute the variance of the revenue is:

V(R)= (Cost\ of\ X)^{2} \times V(X)

Compute the expected revenue as follows:

E(R)=Cost\ of\ X\times E(X)\\= 0.30\times 125\\=37.5

Thus, the expected revenue is $37.50.

Compute the variance of the revenue as follows:

V(R)= (Cost\ of\ X)^{2} \times V(X)\\=(0.30)^{2}\times 50\\=4.5

Thus, the variance of the revenue is $4.50.

7 0
4 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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