I need help with math

Mathematics

1 answer:

jekas [21]4 years ago

7 0

Hello there!

Answer: $7\frac{1}{5}$

When we do area, we simply multiply both the height and the width.

Convert mixed numbers into improper fractions.

And by this, we simply multiply both fractions, and we get out answer as what;s listed above.

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the altitude of the hypotenuse of a right triangle divides the hypotenuse into segments of lengths 14 and 8. what is the length

lisov135 [29]

Answer:

B. $4\sqrt{7}$

Step-by-step explanation:

The right triangle altitude theorem states that the altitude of a right angled triangles formed on the hypotenuse is equal to the geometric mean of the 2 line segments it creates.

This can be represented as:

$h = \sqrt{(xy)}$

Where,

h = the length of the altitude,

x and y are the lengths of the 2 segments formed.

Therefore, the length of the altitude = $h = \sqrt{(14*8)}$

$h = \sqrt{112}$

$h = \sqrt{16}*\sqrt{7}$

$h = 4\sqrt{7}$

3 0

4 years ago

An inequality is shown: −np − 4 ≤ 2(c − 3) Which of the following solves for n?

sesenic [268]

Answer:

$\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p0}$

Step-by-step explanation:

$-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}$