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3 years ago

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If A=(0,0) and B=(8,2) what is the length of AB... Please help I need to get through this D: I have the photo if yall need more

info <3

2 answers:

agasfer [191]3 years ago

4 0

The correct choice is d

lesya692 [45]3 years ago

4 0

8.2462112512353 is the distance between the two points.

Just Google the formula and insert all the into into it and solve.

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A car is traveling at a steady speed. It travels 1 3/4 miles in 2 1/3 minutes. How far will it travel in 45 minutes? In 1 hour?

mina [271]

Answer:

33.75 miles in 45 minutes,

45 miles in an hour

Step-by-step explanation:

45 minutes: 2 1/3= 7/3 ---> 7/3*3=7,

1 3/4= 7/4 ---> 7/4*3=5.25

car travels 5.25 miles for every 7 minutes,

45/7*5.25= 33.75 miles

1 hour (60 minutes):

using that the car travels 5.25 miles for every 7 minutes,

60/7*5.25= 45 miles

Hope that makes sense!

3 0

3 years ago

The graph above is a transformation of the function x2 Write an equation for the function graphed above

lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

$(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2) \ \ \ \ y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \ \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right \\$

We summarize (1) and (3):

$2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.$

Substitute b=-1 into (2):

$9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\$

From (5) subtract (4):

$8a=4\ |:8\\a=0,5.\ \ \ \ \Rightarrow\\$

Substitute a=0,5 into (4):

$0,5+c=-1\\c=-1,5.$

Hense:

y=0,5x²-x-1,5.

5 0

2 years ago

Which planet revolves slowly around the Sun, has rings, and is known for its Great Red Spot?

tresset_1 [31]

It’s a Jupiter hope this held you

5 0

3 years ago

Read 2 more answers

Least to greatest -.6 -5/8 -7/12 -.72

svlad2 [7]

It would be:

-.72 < -5/8 < -.6 < -7/12

4 0

3 years ago

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12

melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

The probability that a passenger does not show up is 0.10:

This means that the probability of showing up is 1-0.1 = 0.9. So $p = 0.9$

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets

This means that $n = 125$

Using the approximation:

$\mu = E(X) = np = 125*0.9 = 112.5$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.9*0.1} = 3.354$

(a) What is the probability that every passenger who shows up can take the flight

This is $P(X \leq 120)$ , so this is the pvalue of Z when X = 120.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{120 - 112.5}{3.354}$

$Z = 2.24$

$Z = 2.24$ has a pvalue of 0.9875

98.75% probability that every passenger who shows up can take the flight

7 0

3 years ago