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3 years ago

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If A=(0,0) and B=(8,2) what is the length of AB... Please help I need to get through this D: I have the photo if yall need more

info <3

2 answers:

agasfer [191]3 years ago

4 0

The correct choice is d

lesya692 [45]3 years ago

4 0

8.2462112512353 is the distance between the two points.

Just Google the formula and insert all the into into it and solve.

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Kai lives 3 kilometers from school, Brea lives 30,000 meters from school, and Cal lives 30,000 centimeters from school. Which st

Sedbober [7]

Answer:

D. Brea lives the farthest from school

Step-by-step explanation:

The easiest way to go about this is to get them all to the same unit. Let's do meters :)

3 kilometers = 3,000 meters (Kai)

30,000 centimeters = 300 meters (Cal)

and then of course 30,000 meters is already in the correct unit (Brea)

Given all of this, you can easily tell that the answer is D

6 0

3 years ago

Slove : 28/36 = 14/y

Dafna1 [17]

Answer:

y = 18

Step-by-step explanation:

<h3><u>i</u><u>)</u><u> </u><u>redu</u><u>ce</u><u> the</u><u> fraction</u><u> </u><u>with</u><u> </u><u>4</u></h3>

$\frac{28}{36} = \frac{14}{y}$

$\frac{28 \div 4}{36 \div 4} = \frac{14}{y}$

$\frac{7}{9} = \frac{14}{y}$

<h3><u>ii</u><u>)</u><u> </u><u>simpl</u><u>ify</u><u> the</u><u> </u><u>eq</u><u>uation</u><u> </u><u>with</u><u> </u><u>cross</u><u> </u><u>multiplication</u></h3>

$\frac{7}{9} = \frac{14}{y}$

$7y = 14 \times 9$

$7y = 126$

<h3>iii) <u>divi</u><u>de</u><u> both</u><u> sides</u><u> of</u><u> the</u><u> equation</u><u> </u><u>by</u><u> </u><u>7</u></h3>

<u> $\frac{7y}{7} = \frac{126}{7}$ </u>

<u> $y = 18$ </u>

7 0

3 years ago

Read 2 more answers

Nastasia [14]

5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>

<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>

d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>

<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),

The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N

4 0

4 years ago

A police car leaves a crime scene heading east directly towards the hospital at 72 kilometres per hour. An ambulance leaves a qu

Vaselesa [24]

Answer:

I'm not sure what the answer is but I will tell you when I get it

8 0

3 years ago

2root 3 x 3 root 8 fully simplified

LuckyWell [14K]

Answer:

$12\sqrt{6}$

Step-by-step explanation:

<h3>Given expression</h3>

$2 \sqrt{3} *3\sqrt{8}$

<h3>Simplify the expression in steps as below</h3>

$2 \sqrt{3} *3\sqrt{8} =$
$2 \sqrt{3} *3\sqrt{2^2*2} =$
$2 \sqrt{3} *3*2\sqrt{2} =$
$2*6* \sqrt{3} *\sqrt{2} =$
$12* \sqrt{3*2} =$
$12\sqrt{6}$

Used properties in solution process:

$\sqrt{a^2} =a$
$\sqrt{a}\sqrt{b} =\sqrt{ab}$

8 0

2 years ago