if a rectangle has an area of 30 square meters and a perimeter of 34 meters . what is the dimensions of the rectangle?
1 answer:
P=2(L+W) and P=34 so
2(L+W)=34
L+W=17 so we can say
L=17-W
A=LW using L from above
A=(17-W)W
A=17W-W^2 and A=30 so
30=17W-W^2
W^2-17W+30=0
W^2-2W-15W+30=0
W(W-2)-15(W-2)=0
(W-15)(W-2)=0
So the dimensions of the rectangle are 15 meters by 2 meters.
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Simplify both sides then isolate the variable
t=10
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8+8= 16
Step-by-step explanation: