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Colt1911 [192]
3 years ago
7

If you toss an unfair coin such that p(heads)=0.45, what is the probability that you get your first heads on the 6th toss?

Mathematics
1 answer:
nalin [4]3 years ago
6 0
Answer: The percent that you get your first heads on the 6th toss is about 2.26%.

To reach this event, you would have to flip a tails 5 times in a row. Then, you would have to flip a heads.

If we multiplied all the percent together, it would look like:

0.55 x 0.55 x 0.55 x 0.55 x 0.55 x 0.45

Multiplying those gives a value of 2.26%.
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2 3/8 - 4 1/2 + 3 1/8 - (1/2)
UkoKoshka [18]

let's convert the mixed fractions to improper fractions firstly.

\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{19}{8}-\cfrac{9}{2}+\cfrac{25}{8}-\cfrac{1}{2}\implies \stackrel{\textit{using an LCD of 8}}{\cfrac{(1)19-(4)9+(1)25-(4)1}{8}}\implies \cfrac{19-36+25-4}{8} \\\\\\ \cfrac{4}{8}\implies \cfrac{1}{2}

8 0
3 years ago
3/4 and 10/12.<br><br> equivalent<br> not equivalent
BigorU [14]

Answer:

3/4 and 10/12 is NOT EQUIVALENT

in order for these to be equivalent, it would have to be 9/12

Step-by-step explanation:

May I have brainliest please? :)

8 0
3 years ago
Read 2 more answers
The perimeter of a rectangular field is 336 m. If the length of the field is 89 m, what is its width?​
exis [7]
The length of the field will be calculated as:
P=2(L+W)
P=376
W=89
thus substituting the values in the equation we get;
376=2(L+89)
376/2=(L+89)
solving for L;
188=L+89
L=188-89
L=99 yards
therefore the length is 99 yards

Hope it helps!
7 0
3 years ago
When I solve this problem I get a big number, and I don't kwow if it's Ok:
Jlenok [28]

Answer:

undefined

Step-by-step explanation:

6 0
3 years ago
Part 1
Dmitrij [34]

Answer:

a)  A n  (B' n C') =  {3, 9}.

b) (AUB) n (BUC) = {2,4,5,6,7,8}

Step-by-step explanation:

a)  Rewriting C ; C = {4,5,6,7,8}

B' = {3,5,7,9} and C' = {2, 3, 9}

so (B' n C') = {3, 9}

and A n  (B' n C') =  {3, 9}.

b)  {A U B} = { 2,3,4,5,6,7,8,9} and {B U C} = {2,4,5,6,7,8}

so (AUB) n (BUC) = {2,4,5,6,7,8}

4 0
3 years ago
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