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Colt1911 [192]
3 years ago
7

If you toss an unfair coin such that p(heads)=0.45, what is the probability that you get your first heads on the 6th toss?

Mathematics
1 answer:
nalin [4]3 years ago
6 0
Answer: The percent that you get your first heads on the 6th toss is about 2.26%.

To reach this event, you would have to flip a tails 5 times in a row. Then, you would have to flip a heads.

If we multiplied all the percent together, it would look like:

0.55 x 0.55 x 0.55 x 0.55 x 0.55 x 0.45

Multiplying those gives a value of 2.26%.
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sleet_krkn [62]
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Solve for x in the simplest form 11=1/2x+8
lesya692 [45]

Answer:

x = 6

Step-by-step explanation:

11 = 1/2x + 8

-> Move 8 to left side

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->We can switch sides so 1/2x is on the left and 3 is on the right

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Step-by-step explanation:

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Answer:

Final potential energy = 24 Joule

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Step-by-step explanation:

<u>Given:</u>

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a) Formula for Potential Energy:

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Where m is the mass of object

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Putting the values of m, g and h

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b) Formula for initial and final velocity:

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where v is the final velocity

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g is acceleration due to gravity and

h is the height obtained by object

here v = 0 at the height 8 m because it will come to rest at the point it attains the maximum height.

h = 8m

g = -10 ms^{-2} (negative because the object's velocity is decreasing)

Putting the values to find 'u':

0^{2}   =u^{2} +2 \times -10 \times 8\\\Rightarrow u^{2} = 160\\\Rightarrow u = 4 \sqrt{10}\ m/s

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3 years ago
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Lapatulllka [165]

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you need to divide the 45 pupils into 60 and 40 percent to

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