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zysi [14]
3 years ago
7

Paula's grades on her history tests this semester are: 79,93, 92, 86, and

Mathematics
2 answers:
Vinvika [58]3 years ago
5 0

Answer:

4.4

Step-by-step explanation:

Data set = 79, 93, 92, 86, 90

Xmean = (79 + 93 + 92 + 86 + 90)/5

= 440/5

Xmean = 88

MAD =

(79 - 88) + (93 - 88) + ( 92 - 88) + ( 86 - 88) + ( 90 - 88)/ 5

=

(9) + (5) + (4) + (2) + (2)/ 5

=

22/5

Mean Absolute Deviation = 4.4

bagirrra123 [75]3 years ago
4 0

Answer:

The MAD is 4.4.

Step-by-step explanation:

1. 79+93+92+86+90/5= 88= Mean.

2. Apply |values - mean| 9+5+4+2+2=22

3. Divide by total of values, 22/5= 4.4.

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<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

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(3Q) Find the amplitude and period of f(t)= -tan.0t
Vanyuwa [196]

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Step-by-step explanation:

Given a function of the following type:

f(t) = AtanB(t + C)

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In this case, we have f(t)= -tan0.4t. Then:

B = 0.4

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3 years ago
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Serga [27]

Answer:

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Step-by-step explanation:

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y =  - 3 {x}^{2}  + 48x  - 195

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