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Burka [1]
3 years ago
8

Which point is the midpoint of segment AB?

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

it is 0.

0 is the midpoint.

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Carol opened 20 different bags of the same kind of candy and recorded the colors and their frequencies, as shown in the table.
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It is 14% as you add up all of the numbers and divide 10 by that number and finally multiply by 100 for a percent
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3 years ago
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MORE EASY 7TH GRADE MATH<br><br> X/2=95 <br><br><br> THANK YOU
SIZIF [17.4K]

Answer:

X/2=95

X= 95*2

X=190

Step-by-step explanation:

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Find the vertices of the hyperbola. Enter the smallest coordinate first.
melisa1 [442]

Answer:

([-3], [0]), ([3], [0])

Step-by-step explanation:

The given equation of the hyperbola is presented as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = 1

The vertices of an hyperbola (of the form)  \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 are (± a, 0)

The given hyperbola can we presented in a similar form as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = \dfrac{x^2}{3^2} - \dfrac{y^2}{7^2} = 1

Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;

The vertices of the parabola are ([-3], [0]), ([3], [0]).

4 0
3 years ago
Voltage = 18v. Current = 36 amps resistance =?
kupik [55]
Voltage= Current * Resistance
Plug in your values and solve for 'x' or resistance
8 0
3 years ago
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
2 years ago
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