Answer:
y = –12x –300 that will help you
<span>Lets calculate an example:
Say, .001% of tires that come from the factory are bad. There is a 1/1000 chance that for any given tire randomly selected from the warehouse that a defect will be present. Each tire is a mutually exclusive independently occurring event in this case. The probability that a single tire will be good or bad, does not depend on how many tires are shipped in proportion to this known .001% (or 1/1000) defect rate.
To get the probability in a case like this, that all tires are good in a shipment of 100, with a factory defect rate of .001%, first divide 999/1000. We know that .999% of tires are good. Since 1/1000 is bad, 999/1000 are good. Now, multiply .999 x .999 x .999..etc until you account for every tire in the group of 100 shipped. (.999 to the hundredth power)
This gives us 0.90479214711 which rounds to about .90. or a 90% probability.
So for this example, in a shipment of 100 tires, with a .001% factory defect rate, the probability is about 90 percent that all tires will be good.
Remember, the tires are mutually exclusive and independent of each other when using something like a factory defect rate to calculate the probability that a shipment will be good.</span>
Answer:
chance of winning $100 = 1/1000
chance of winning $50 = 5/1000 = 1/200
cost of ticket = -1
E[x] = 100* 1/1000 + 50* 1/200 -1
= 0.1 + 0.25 - 1 = -0.65
Step-by-step explanation:
hope this helps
Answer:
<h2>d. 1,196,000 gal</h2>
Step-by-step explanation:
Number of students = 525+625=1 150
The number of people = 525+625+58+12=1 220
let x represent the amounot of water consumed by students
1220———————>1 267 760
1150———————> x
then
x = (1 150×1 267 760)÷1 220 = 1 195 019.67213115
:)
Six is A there is your answer