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fenix001 [56]
3 years ago
12

One should continue to monitor his or her goals and adjust his or her plan for achieving them when it is necessary A:true B:fals

e
Mathematics
2 answers:
kupik [55]3 years ago
5 0
Oh for sure, true true true! A good example would be a workout routine, find out what best works.
Ksenya-84 [330]3 years ago
3 0
Yes, I believe that's true.
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Can someone please help me? I don't know how to do this. I will mark brainliest! Thanks!
Bezzdna [24]

Answer:

So it gives you a little picture and tells you what would the question be if you had this graph.

Step-by-step explanation:

The correct answer would be B, find the area because the 4x + 3 is your length and 3x is your length, A = length * width. So the answer is B, find the area.

4 0
3 years ago
Read 2 more answers
(20) points and brianliest) Write the equation of a line which contains the point (4,3) and (2,5). Remember you must first find
lions [1.4K]
Slope formula
y2-y1/x2-x1
5-3/2-4
2/-2
-1 = slope

y=-1x+b
5=-1(2)+b
5=-2+b
b=7

Your answer:
y= -1x + 7
3 0
3 years ago
Name two intersecting line segments that are not perpendicular.
liubo4ka [24]
I don't see anything, but any line that doensnt have the right angle sign is not perpendicular. 
4 0
3 years ago
Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn's
Lina20 [59]

Answer:

The percent error is -2.1352% of Jocelyn's estimate.

6 0
3 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
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