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3 years ago

Given 6(x) = |x+41, what is b(-10)?

Mathematics

1 answer:

Bess [88]3 years ago

5 0

Answer:37.93

Step-by-step explanation:

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Estimate the sum by first rounding each

sukhopar [10]

5 3/8 rounds to 5,
4 7/10 rounds to 5
Your estimated sum is 10

5 0

2 years ago

Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

1 year ago

1. 22 is 11% of what number? I NEED HELP URGENTLY

Naddika [18.5K]

2.42 is the answer ps.are u from k12? I am

6 0

2 years ago

Read 2 more answers

Solve the system of equations. 3x – 4y = 8 18x – 5y = 10 x= y =<br>

Zepler [3.9K]

Answer:

Step-by-step explanation:

Solution by substitution method

3x-4y=8

and 18x-5y=10

Suppose,

3x-4y=8→(1)

and 18x-5y=10→(2)

Taking equation (1), we have

3x-4y=8

⇒3x=4y+8

⇒x=( 4y+8)/ 3 →(3)

Putting x= (4y+8 )/3 in equation (2), we get

18x-5y=10

18( (4y+8) /3) -5y=10

⇒24y+48-5y=10

⇒19y+48=10

⇒19y=10-48

⇒19y= -38

⇒y=- 38 /19

⇒y= -2→(4)

Now, Putting y=-2 in equation (3), we get

x=4y+8

x= (4(-2)+8) /3

⇒x= (-8+8)/ 3

⇒x= 0/ 3

⇒x=0

∴x=0 and y= -2

5 0

2 years ago

what measuring tool did ancient mathematics have and how do they compare to the measuring tools we have today?

german

Answer:

Search it up my guy itsthere

Step-by-step explanation:

3 0

2 years ago