Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
Answer:
see explanation
Step-by-step explanation:
These are the terms of a geometric sequence with n th term
= a
where re a is the first term and r the common ratio
r = 9 ÷ - 3 = - 27 ÷ 9 = 81 ÷ - 27 = - 3 ← common ratio
and a = - 3, thus
[te x]a_{n}[/tex] = - 3
← explicit formula
If this is talking about the Pythagorean theorem then it would be 5,12,13 becuase because the equation for the triangle is
2 2 2
a + b = c
2 2 2
5 + 12. = 13
so if x = -1, let's plug that in the second equation
-5(-1)+y = 5
5+y = 5
y = 0
Answer:
https://web.williams.edu/Mathematics/sjmiller/public_html/105/hwsolns/HWSolns_Math105_Sp2013.pdf click the link
Step-by-step explanation:
