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astraxan [27]
3 years ago
7

6х + 4ув 32-6х + 4 y = 8​

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

The Solution set is (x,y){(2,5)}

Step-by-step explanation:

The given equation is:

  6x+4y=32

 -6x+4y=8

We will use the elimination method:

By this method we will eliminate the variable x.

6x+4y=32

-6x+4y=8

________

      8y=40

Divide both the sides by 8

8y/8=40/8

y=5

Now substitute the value of y in equation 2:

-6x+4y=8

-6x+4(5)=8

-6x+20=8

Move the constant value to the R.H.S

-6x=8-20

-6x= -12

Divide both the terms by -6

-6x/-6 = -12/-6

x= 2

The Solution set is (x,y){(2,5)}....

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